在Go正则表达式中分割浮点字符串

Question

I'm, trying to split a certain string type to its constituents using Golang's regex.

What I have is a Sprinf(".2f", n) of any given float (to simplify it to 2 decimal places), and would wish to separate the hundredths digit like:

"1.25" = ["1.2", "5"]
"1.99" = ["1.9", "9"]

In PHP, this is something like:

preg_match('/^ (\-? \d [.] \d) (\d) $/x', sprintf('%1.2f', $input), $matches)

and I can get the parts via $matches[0] and $matches[1].

Tried it with :

re := regexp.MustCompile(`/^ (\-? \d [.] \d) (\d) $/x`)
fmt.Printf("%q
", re.FindAllStringSubmatch("1.50", 2))

to no avail. Thanks in advance.

Answer 1

Why do you need regexp for this? Simply slice the string:

func split(s string) []string {
    if len(s) == 0 {
        return nil
    }
    return []string{s[:len(s)-1], s[len(s)-1:]}
}

Testing it:

nums := []string{
    fmt.Sprintf("%.2f", 1.25),
    fmt.Sprintf("%.2f", 1.99),
    fmt.Sprintf("%.2f", 1.25),
    fmt.Sprintf("%.2f", 1.2),
    fmt.Sprintf("%.2f", 0.0),
    fmt.Sprintf("%.2f", -1.2),
    "",
}
for _, n := range nums {
    fmt.Printf("%q = %q
", n, split(n))
}

Output (try it on the Go Playground):

"1.25" = ["1.2" "5"]
"1.99" = ["1.9" "9"]
"1.25" = ["1.2" "5"]
"1.20" = ["1.2" "0"]
"0.00" = ["0.0" "0"]
"-1.20" = ["-1.2" "0"]
"" = []