我可以在Go中使用unsafe.Pointer将* interface {}转换为* int吗

Question

I am making a memory pool in Go.
I am doing so because implicit converting int to interface{} will trigger a memory allocation.I want to avoid the allocation.
I want to allocate several types of pointers in one pool.
The pool is something like this.

type creator struct{
    buf []interface{}
}
func (cr *creator) Create()*interface{}{
    if len(cr.buf)==0{
        cr.buf=make([]interface{},256)
    }
    current:=&cr.buf[0]
    cr.buf=cr.buf[1:]
    return current
}

func (cr *creator)CreateInt()*int{
    pointer:=cr.Create()
    return (*int)(unsafe.Pointer(pointer))   // <-- right or wrong?
}

Is the code valid?

Answer 1

You have *interface {} and you want to pretend that it is *int! How is that going to work?

package main

import (
    "fmt"
    "unsafe"
)

func main() {
    var cr creator
    pointer := cr.CreateInt()
    fmt.Printf("%T
", pointer) // *int
}

type creator struct {
    buf []interface{}
}

func (cr *creator) Create() *interface{} {
    if len(cr.buf) == 0 {
        cr.buf = make([]interface{}, 256)
    }
    current := &cr.buf[0]
    cr.buf = cr.buf[1:]
    return current
}

func (cr *creator) CreateInt() *int {
    pointer := cr.Create()
    fmt.Printf("%T
", pointer)            // *interface {}
    return (*int)(unsafe.Pointer(pointer)) // *interface {} to *int
}

Playground: https://play.golang.org/p/TLF7kbYPA0M

Output:

*interface {} 0x452000
*int 0x452000