如何在Golang中将int16转换为十六进制编码的字符串

Question

I need to convert the data format of an int16 to a string representing its hexadecimal value.

I have tried some hex converters but they change the data instead of changing the formatting. I need it to be a string representation of its hexadecimal value.

data := (data from buffer)

fmt.Printf("BUFFER DATA : %X
", data) // output print on screen D9DC (hex)
fmt.Println(("BUFFER DATA : ", string(data)) // output print on screen 55772 (dec)
fmt.Println(("BUFFER DATA : ", data) // output print on screen [?]

How can I convert the data format so it prints D9DC with fmt.Println?

Full code here https://play.golang.org/p/WVpMb9lh1Rx

Answer 1

Since fmt.Println doesn't accept format flags, it prints each variable depending on its type.

crc16.Checksum returns an int16, so fmt.Println will display the integer value of your hexadecimal string, which is 55772.

If you want fmt.Println to print D9DC instead of the integer value, you have multiple choices.

• Convert your integer into a string that contains the hexadecimal value (which means if you change your integer, you will need to convert it into a string again before using it
• Create your own type with a String() method, which is an integer but is represented by its hexadecimal value when printed.

For the second option, your type could be something like this:

type Hex int16

func (h Hex) String() string {
    return strconv.FormatInt(int64(h), 16)
}

fmt.Println will automatically use this method because it means the Hex type implements the Stringer interface. For more info on this, here are some resources:

• https://tour.golang.org/methods/17
• https://golang.org/pkg/fmt/#Stringer