在Golang中将uint64转换为字符串

Question

我正试图打印 string 和 uint64 但是我使用的strconv方法的组合是无效的。

log.Println("The amount is: " + strconv.Itoa((charge.Amount)))

给我的提示是：

cannot use charge.Amount (type uint64) as type int in argument to strconv.Itoa

那么我该如何打印 string这个呢？

Answer 1

strconv.Itoa() expects a value of type int, so you have to give it that:

log.Println("The amount is: " + strconv.Itoa(int(charge.Amount)))

But know that this may lose precision if int is 32-bit (while uint64 is 64), also sign-ness is different. strconv.FormatUint() would be better as that expects a value of type uint64:

log.Println("The amount is: " + strconv.FormatUint(charge.Amount, 10))

For more options, see this answer: Golang: format a string without printing?

If your purpose is to just print the value, you don't need to convert it, neither to int nor to string, use one of these:

log.Println("The amount is:", charge.Amount)
log.Printf("The amount is: %d
", charge.Amount)