2016-08-03 02:56

# 将Struct数组元素作为参数传递给Go语言中的函数

I have defined a function `possiblemoves()`, that takes in two integers as parameters, but later I want this function to make a call to all the elements in `Struct array` recursively I didn't put the terminating condition yet, I will do it once I finish it

Code:

``````package main

import (
"fmt"
)

/*type node struct{
prev node
current node
Next [64] int
}*/
type rowcol struct {
row int
col int
}

func main() {
possiblemoves(1, 5)
}
func possiblemoves(row int, col int) {
var c [8]rowcol
var a [16]int

a[0] = row + 1
a[1] = col - 2
a[2] = row - 1
a[3] = col + 2
a[4] = row + 1
a[5] = col + 2
a[6] = row - 1
a[7] = col - 2
a[8] = row - 2
a[9] = col + 1
a[10] = row - 2
a[11] = col - 1
a[12] = row + 2
a[13] = col - 1
a[14] = row + 2
a[15] = col + 1

for i := 0; i < len(a); i++ {
if a[i] <= 0 {
a[i] = 0
}
fmt.Println(a[i])
}

c[0] = rowcol{a[0], a[1]}
c[1] = rowcol{a[2], a[3]}
c[2] = rowcol{a[4], a[5]}
c[3] = rowcol{a[6], a[7]}
c[4] = rowcol{a[8], a[9]}
c[5] = rowcol{a[10], a[11]}
c[6] = rowcol{a[12], a[13]}
c[7] = rowcol{a[14], a[15]}

for j := 0; j < len(c); j++ {
{
possiblemoves(c[j])
}
}

}
``````
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#### 1条回答默认 最新

• dongzhang5787 2016-08-03 03:24
已采纳

Simply do

``````type rowcol struct {
row int
col int
}

func possiblemoves(rc []rowcol) {}

func main() {
rc := []rowcol{
rowcol{1, 2},
rowcol{3, 4},
}
possiblemoves(rc)
}
``````

https://play.golang.org/p/dQ1edTJNhq

`[]rowcol` is a slice of `rowcol` structs. Then you use `rc[1].row` and `rc[1].col` to access these struct fields.

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