dongxue9997 2015-07-12 04:59
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Float64输入go中的常量,失去精度

Consider the following code written in go:

package main

import "fmt"

func main() {
    const pi float64 = 22 / 7
    fmt.Println("pi value", pi)
}

here the value of pi is 3. The question is why is the value losing precision even though it is of type float64?

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  • doudui2229 2015-07-12 05:02
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    NeverMind, I got the answer.

    package main
    
    import "fmt"
    
    func main() {
        const pi float64 = 22.0 / 7.0
        fmt.Println("pi value", pi)
    }
    

    Output 3.142857142857143. it seems types depend if type integer are be divided, it will return a integer regardless if the receiving var is type float64. so get a float value, devision has you occur between float values.

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