在map [string] interface {}中检查多个键时使用OR逻辑

Question

I have a map[string]interface{} called mapped:

mapped map[stringinterface{}

I want to iterate through it checking to see if either of these keys exist:

• columns
• rows

Then if so, I want to append the row or column to a slice of strings called:

• columnOrRowArray

I understand that if I just needed to find, for example columns, within mapped I can do this:

var columnOrRowArray []string

if columnsOrRows, ok := mapped["columns"].([]interface{}); ok {
    for _, columnOrRow := range columnsOrRows {
        if columnOrRowValueIsString, ok = columnOrRow.(string); ok {
            columnOrRowArray = append(columnOrRowArray, columnOrRowValueIsString)
        }
    }
}

What would be a clean way without me duplicating the above for using row logic for the mapped["rows"]?

I want to do something that is basically this:

columnsOrRows, ok := mapped["columns"].([]interface{}) || mapped["rows"].([]interface{}); ok {

So in plain English, "if mapped has a the column or row key, assign to variable columnsOrRows"

Obviously I know the syntax for that is wrong, but I can't find an example of someone doing this

Answer 1

Test for both keys:

columnsOrRows, ok := mapped["columns"].([]interface{})
if !ok {
    columnsOrRows, ok = mapped["rows"].([]interface{})
}

if ok {
    for _, columnOrRow := range columnsOrRows {
        if columnOrRowValueIsString, ok = columnOrRow.(string); ok {
            columnOrRowArray = append(columnOrRowArray, columnOrRowValueIsString)
        }
    }
}