从Go中的float32转换为int

Question

I have tried several ways to cast a float to an int, what I want is to truncate a float so I only get the integer part. I'm using

x := float32(3.1)
y,_ := strconv.Atoi((strconv.Ftoa32(x,'f',0))) //y becomes 3

But if x is 3.9, y will become 4 because this function will round the float32 instead of truncating. Is there a way of truncating instead of rounding? and if so, is it possible to do it without involving strings? (like casting a float to int in C)

Answer 1

Just use int():

x := float32(3.1)
fmt.Println(int(x))

Which produces 3 as needed, without having to use string conversions or the like.