在Golang中更新grpc的接收和发送消息大小

Question

I have grpc server written in Go and I am trying to update receive and send message size to 20MB instead of the default 4MB with the following code

var s *grpc.Server
s = grpc.NewServer(grpc.MaxRecvMsgSize(1024*1024*20), grpc.MaxSendMsgSize(1024*1024*20))

pb.RegisterProductServer(s,mysrv)

But the above doesn't seem to be working as I still get an error when I tried to call from a client received message larger than max (5807570 vs. 4194304)" Not sure whats overriding the size

Answer 1

I haven't had the chance to test this yet but have you tried adding the same options from the client stub? The same options can be attached as dial options:

maxMsgSize := 1024*1024*20
conn, err := grpc.Dial(address, grpc.WithDefaultCallOptions(grpc.MaxRecvMsgSize(maxMsgSize), grpc.MaxSendMsgSize(maxMsgSize)))
if err != nil {
    // ...
}
defer conn.close()
client := pb.NewProductClient(conn)
// ...

I don't know anything about your use case but if your response data can be delivered piece wise then the streaming APIs might be useful.