dongtan7639 2019-01-10 22:32
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在Golang中更新grpc的接收和发送消息大小

I have grpc server written in Go and I am trying to update receive and send message size to 20MB instead of the default 4MB with the following code

var s *grpc.Server
s = grpc.NewServer(grpc.MaxRecvMsgSize(1024*1024*20), grpc.MaxSendMsgSize(1024*1024*20))

pb.RegisterProductServer(s,mysrv)

But the above doesn't seem to be working as I still get an error when I tried to call from a client received message larger than max (5807570 vs. 4194304)" Not sure whats overriding the size

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  • douming4359 2019-01-11 02:45
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    I haven't had the chance to test this yet but have you tried adding the same options from the client stub? The same options can be attached as dial options:

    maxMsgSize := 1024*1024*20
    conn, err := grpc.Dial(address, grpc.WithDefaultCallOptions(grpc.MaxRecvMsgSize(maxMsgSize), grpc.MaxSendMsgSize(maxMsgSize)))
    if err != nil {
        // ...
    }
    defer conn.close()
    client := pb.NewProductClient(conn)
    // ...
    

    I don't know anything about your use case but if your response data can be delivered piece wise then the streaming APIs might be useful.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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