普通网友 2018-05-21 19:58
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为什么当类型实现接口时,行为会有所不同?

Who can tell (or link where to read), why when a type do implementing an interface there is a difference in behavior (depending on how to transfer the recipient)? Here so it works:

type GetNamer interface {
  GetName()
}

type Person struct {
  PersonName string
}

func (p Person) GetName() {
  fmt.Println(p.PersonName)
}

type Data []GetNamer

var d = Data{
    Person{"Vasya"},
  }

But, if I pass the recipient by the link: (p *Person) I get an error that types (Person and GetNamer) do not match.

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1条回答 默认 最新

  • droos02800 2018-05-21 20:06
    关注

    The reason is that when you change the receiver signature to (p *Person) it means that *Person implements the interface, not Person, so your "Data" array must be changed to match.

    That is, you must change the signature of the interface method and the contents of the "d" variable to contain Person pointers and it should work, since &Person{...} is a *Person which is a GetNamer:

    func (p *Person) GetName() {
      // ...
    }
    
    var d = Data{
      &Person{"Vasya"},
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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