将行尾转换为“ ”文字

Question

I have an interesting problem to solve. Because of a tool that I have to talk to, I need to convert newlines to the literal string I have the following data

{"name": 2019-05-25,
"tracker": {
"project": {
  "uri": "/project/87",
  "name": "Allen's Test"
},
"uri": "/tracker/57483",
"name": "Tasks"
        },
"description": "[{Table

||Stack
||Current Version
||New Version
||Changes
|common
|1.0.214
|1.0.214
|* blah - [#345|https://blah.com/345]

|workflow
|2.2.23
|2.2.23
|* [ES-12345] blah - [#1087|https://blah.com/1087]

}]",
"descFormat": "Wiki"}

so basically instead of a multiline string, I need to convert it to a single line string with 's where the tool on the backend will convert it. I'm using go and not quite sure where to start. I asssume I need raw strings, but many of the source bits are api calls that have the newlines built in.

Any help would be appreciated.

Answer 1

For example,

package main

import (
    "fmt"
    "strings"
)

func main() {
    s := `"project": {
  "uri": "/project/87",
  "name": "Allen's Test"
},`
    fmt.Println(s)
    s = strings.ReplaceAll(s, "
", `
`)
    fmt.Println(s)
}

Playground: https://play.golang.org/p/lKZw78yOuMc

Output:

"project": {
  "uri": "/project/87",
  "name": "Allen's Test"
},
"project": {
  "uri": "/project/87",
  "name": "Allen's Test"
},

---

For before Go 1.12, write:

s = strings.Replace(s, "
", `
`, -1)