如何将字符串转换为int128值？ 目前我仅限于int64

Question

Given, stringvalue := "zzzzzzzzzzzzzzzzzzzz"

   i, err := strconv.ParseInt(stringvalue, 36, 0)

How do I return int128 as my stringvalue will be long enough to return int128?

Answer 1

There is no Go type int128. Use the Go math/big package type Int.

For example,

package main

import (
    "fmt"
    "math/big"
)

func main() {
    z, ok := new(big.Int).SetString("zzzzzzzzzzzzzzzzzzzz", 36)
    if ok {
        fmt.Println(z)
        fmt.Println(z.Text(36))
    }
}

Playground: https://play.golang.org/p/ln1PswhmK-l

Output:

13367494538843734067838845976575
zzzzzzzzzzzzzzzzzzzz