类模板实例化时，如果模板类型是另一个类，那是怎么运行的？

Question

#include<String>
struct Person
{
    std::string name;
    int age;
    Person(std::string n, int a) :name(n), age(a)
    {
    }
    Person()
    {
    }

};

namespace VGP130
{
    template<typename T, size_t n>
    class Stack
    {
    public:
        explicit Stack() :top(-1), size(n)
        {

        }
        ~Stack() = default;
        bool push(const T& a)
        {
            if (!isFull())
            {
                data[++top] = a;
                return true;
            }
            return false;
        }

        bool isFull() const
        {
            return top == size - 1;
        }
        bool isEmpty()const
        {
            return top == -1;
        }
        bool pop(T& ret)
        {
            if (isEmpty())
                return false;
            ret = data[top--];
            return true;
        }

        void print()
        {
            std::cout << "Stack: ";
            for (int i = 0; i <= top; ++i)
                std::cout << data[i] << std::endl;
            std::cout << std::endl;

        }
    private:
        T data[n];
        int top;
        size_t size;
    };

}


#include<iostream>
#include "Person.h"
#include "Stack.h"


using namespace std;
using namespace VGP130;


int main()
{

    Stack<Person, 5> personStack;
    for (int i = 0; i < 5; ++i)
    {
        personStack.push(Person("what",2));
    }

    Person pValue{};
    for (int i = 0; i < 5; ++i)
    {
        if (personStack.pop(pValue))
            cout << "Top of peraonStack: " << pValue.name <<" "<<pValue.age <<endl;
        else
            cout << "pop from empty stack" << endl;
    }
    system("pause");

}

stack 是模板类，在main函数里实例化的时候，模板类型T是另一个结构体
Person 
Stack<Person, 5> personStack
请问下面的代码是如何实现的：
    for (int i = 0; i < 5; ++i)
    {
        personStack.push(Person("what",2));
    }
        数据是怎么导入的。

Answer 1

参考：https://www.cnblogs.com/share-happy-everyday/p/9354540.html

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