Ajax PHP HTML表单

Question

I am trying to retrieve multiple rows of data from my database. The number of rows that will be returned is unknown. It works for one row returned. But i also have scenarios where multiple rows are returned to the html page where the ajax function adds the corresponding value to the form.

What is the best way to handle unknown number of rows in an html form? Also is the form a good idea?

I was trying to figure out a way to have the php scipt build the html code and pass it back using ajax. But have been unable to find any sort of examples online.

In the function you can see that I take the data and equate it to the form. The form is predefined to have one entry. but i need to know how to modify the form to know how many records will be returned. I hope that makes sense. Thank you in advanced.

CODE:

function getFunction(){
    //browser support code
    var ajaxRequest; // The variable to create the ajax request
    try {
          // Opera 8.0+, Firefox, Safari Support
          ajaxRequest = new XMLHttpRequest();
    } catch (e){
          try{
                ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
                } catch (e) {
                        try{
                                ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
                        } catch (e){
                                // Something went wrong with the browser support
                                alert("Your browser broke!");
                                return false;
                        }
                }
        }
        // Create a function that will receive data sent from the server
        ajaxRequest.onreadystatechange = function(){
          if(ajaxRequest.readyState == 4){
            // document.write(ajaxRequest.responseText);
            var response = JSON.parse(ajaxRequest.responseText);
            var pfullname=response.pfirstname + " ";
            var dfullname=response.dfirstname + " ";
            if (response.pmiddlename!=null) {pfullname = pfullname + response.pmiddlename + " ";}
            pfullname = pfullname + " " + response.plastname;
            document.info.name.innerHTML = pfullname;
            //document.info.address.value = ajaxRequest.responseText;
            document.info.dob.innerHTML = response.dob;
            document.info.address.innerHTML = response.paddress;
            document.info.phonenumber.innerHTML = response.phonenumber;
            document.info.sex.innerHTML = response.sex;
            document.info.occupation.innerHTML = response.occupation;
            if (response.dmiddlename!=null) {dfullname = dfullname + response.dmiddlename + " ";}
            dfullname = dfullname + response.dlastname;
            document.info.doctorp.innerHTML = dfullname;
            document.appointment.locationa.innerHTML = response.alocation;
            document.appointment.datea.innerHTML = response.adate;
            document.appointment.doctora.innerHTML = dfullname;
          }
        }
        //var testname = document.getElementById('testname').value;
        var healthid = document.getElementById('healthid').value;
        //var queryString = "?testname=" + testname + "&testpassword=" + testpassword;
        var queryString = "healthid=" + healthid;
        //document.write(queryString);
        ajaxRequest.open("POST", "getnum.php", true);
        ajaxRequest.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
        ajaxRequest.send(queryString);

}

PHP CODE:

query($sql)){ while($row = $result->fetch_object()){ echo json_encode($row); } } else{ //error occurred echo 'error:'.$con->error; } mysqli_close($con); ?>

HTML CODE:

    <h2>
      <span style="font-weight:bold;">Patient Information:</span>
      <form name='info'>
        Name:           <output type='text' name="name" id="name"> </output><br>
        DOB:            <output value='' type='text' name="dob" id="dob"> </output><br>
        Address:        <output type='text' name="address" id="address"> </output><br>
        Phone Number:   <output type='text' name="phonenumber" id="phonenumber"> </output><br>
        Sex:            <output type='text' name="sex" id="sex"> </output><br>
        Occupation:     <output type='text' name="occupation" id="occupation"> </output><br>
        Doctor:         <output type='text' name="doctorp" id="doctorp"> </output><br>
        Doctor Address: <output type='text' name="doctoradd" id="doctoradd"> </ouput><br>
      </form>
    </h2>

Answer 1

If you return the data for the multiple rows as an array within your json reponse, eg. in your php:

json_encode(array( array("firstname" => "Bob", "lastname" => "Smith"),
                   array("firstname" => "Harry", "lastname" => "Jones")));

Then in your javascript you can then iterate over this array as Raunak suggests above with something like:

var rows = response.multiplerows

for (i = 0; i < rows.length; i++) {
    //add lines to form here by accessing array data with rows[i].firstname etc.
}

If you are going to do a lot of this sort of thing you may want to look at the likes of knockout.js observable arrays, which can generate the the rows for you based on an html template and the number of lines in the array - http://knockoutjs.com/documentation/observableArrays.html

If in fact you are not needing the data in a form for editing and further manipulation in the browser you may find it easier to return an html chunk to the browser rather than json, and just insert this in the doc, eg. in your php:

$patients = '<h1>List of patients</h1>';

while ($row = $result->fetch_assoc()) {
    $patients .= '<div class="patient-info">First name: '.$row["first_name"].'<br />Last name: '.$row["last_name"].'</div>'; //etc.
}

return $patients;

In your html you can then just have

<div id="patient-list"></div>

And your javascript then will be simply something like:

document.getElementById("patient-list").innerHTML = responseText;