weixin_33737774 2015-03-27 18:59 采纳率: 0%
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Have now got this far with this and think I am getting stuck right at the end!! I have now got both menus being processed by "process.php" and am outputting my queries back into index.php.


$menu1 = $_POST["menu1"];
$menu2 = $_POST["menu2"];

if($menu1 == 0) {
    $sql = "SELECT * FROM Language WHERE ID = " . $menu2;   
} else if($menu1 == 1) {
    $sql = "SELECT * FROM Mathematics WHERE ID = " . $menu2;
} else if($menu1 == 2) {
    $sql = "SELECT * FROM Culture WHERE ID = " . $menu2;

echo $sql;



<!DOCTYPE html>
  <meta http-equiv="content-type" content="text/html; charset=UTF-8">
  <script type='text/javascript' src='https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js'></script>
<script type='text/javascript'>
var data = {
            Language:       ["","Noun Game","Phonetic Noun Box"],
            Mathematics:    ["","Number Rods","Sandpaper Numerals"],
            Culture:        ["","Concept of Time-Clock"]
// populate menu1
for (var i in data) {
    $('#menu1').append('<option>' + i + '</option>');
// populate menu2 based on menu1 value
$('#menu1').change(function() {
    var key = $(this).val();
    for (var i in data[key]) {
        $('#menu2').append('<option>' + data[key][i] + '</option>');

<form id="form" action="process.php" method="post">
  <select id="menu1" name="menu1"></select>
  <select id="menu2" name="menu2"></select>

 <input id="submit" type="submit" value="ENTER" />
<div id="resultsContainer"></div>

       //alert('jQuery loaded');
            menu1value = $('#menu1')[0].selectedIndex;
            menu2value = $('#menu2')[0].selectedIndex;
            return false;


Now I just need to output queries in a table on index.php. Think this will be just about looping through the output but I'm not sure... any help please.

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  • hurriedly% 2015-03-29 08:25

    I'm assuming that you want to populate both of the selects using ajax.

    That said your script will probably be similar to this:

    type: "POST",
    cashe: false,
    url: 'processing-page.php',
    success: function(data){
    // use data to make the options
        $('#menu2').on('click', function(){
    type: "post",
    cashe: false,
    url: 'processing-page.php',
    data: {val1: Val1, val2: Val2},
    success: function(data){
    // make options with the data

    You will have to create a separate php page that will query the database and send results back through ajax.

    Sorry it looks kind of weird. I typed it in on a phone. Let me know if this works for you or if anything needs clarification.

    UPDATE: This is the only way I know how to return multiple values (such as queries) using ajax. In the processing page I format the queries into a string to send back.

    switch ($_POST["menu1"]) {
      case "Language":
        $result1 = mysql_query($sql1);
        $result2 = mysql_query($sql2);
        $result3 = mysql_query($sql3);
        $result4 = mysql_query($sql4); 
      case "Mathematics":
        // and so on...
    $allResults = array($result1, $result2, $result3, $result4);
    $allResultStr = "";  
    // make the queries into strings  
    foreach($allResults as $result){
      $allResultStr = $allResultStr . $result[key1] ."|". $result[key2] . ",";
    $allResultStr = substr($optionArray, 0, -1); // takes the last comma off  
    echo $allResultStr;

    In the script, I take apart the string using the split() function.

    function(data){  // data is $allResultStr
      var options = data.split(",");
      for(var option in options){
        var parts = options[option].split("|");
        var newOption = document.createElement("option");
        // make the option values and text based on the results
        newOption.value = parts[0]; 
        newOption.innerHTML = parts[1];



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