bug^君 2018-08-24 12:14 采纳率: 25%
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成功后调用ajax

I made an ajax request to get the name of each button I click... Then I want to put everything in that url into "#Container".(url define a page that has some codes) It works for me at the first time...but for the other times I have to reload the page to show me the details of each button and it doesn't show me details of other buttons that clicked after first desired button..

$(function () {
  $('button').click(function () {
    var data= $(this).val();
    $.ajax({
      url: '/myurl',
      type: 'post',
      dataType: 'json',
      data: {
        data: data
      },
      success: function (data) {
        $('#container').html(data);
      }
    });
  });
});

What should I do? Is there something preventing of running the ajax for next times ?

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2条回答 默认 最新

  • 乱世@小熊 2018-08-24 12:28
    关注

    Try with $(document).on('click', instead of $('button').click like below

    $(function () {
      $(document).on('click','button',function () {    
      var data= $(this).val();
      alert(data);
      $.ajax({
        url: '/myurl',
        type: 'post',
        dataType: 'json',
        data: {data: data},
        success: function (data) {
          $('#container').html(data);}
        });
      });
    });
    
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