普通网友 2015-09-23 15:22
浏览 37

从对象返回变量

I need to return result variable from this code, I am trying it about hour, but still with no successs... Can You help me please? I studied object too, but without success...

api.prototype.ajax = function()
{
    marmottajax({
                            url: "http://localhost:8080/bp/stranka/api/test",
                            method: "post",
                            parameters: 
                            {
                                image: 8,
                                by: "click"
                            }
                        }).then(function(result) 
                        {
                            result; //this variable i want to get/return to my function
                        });
}
  • 写回答

2条回答 默认 最新

  • csdn产品小助手 2015-09-23 15:25
    关注

    You can't return from an AJAX call - you either need to use promises or a callback. Here's an example with a callback:

    api.prototype.ajax = function(callback) {
        marmottajax({
            url: "http://localhost:8080/bp/stranka/api/test",
            method: "post",
            parameters: {
                image: 8,
                by: "click"
            }
        }).then(function(result) {
            callback(result); //this variable i want to get/return to my function
        });
    }
    

    And use it:

    api.ajax(function(data) {
        console.log(data);
    });
    
    评论

报告相同问题?

悬赏问题

  • ¥15 如何让企业微信机器人实现消息汇总整合
  • ¥50 关于#ui#的问题:做yolov8的ui界面出现的问题
  • ¥15 如何用Python爬取各高校教师公开的教育和工作经历
  • ¥15 TLE9879QXA40 电机驱动
  • ¥20 对于工程问题的非线性数学模型进行线性化
  • ¥15 Mirare PLUS 进行密钥认证?(详解)
  • ¥15 物体双站RCS和其组成阵列后的双站RCS关系验证
  • ¥20 想用ollama做一个自己的AI数据库
  • ¥15 关于qualoth编辑及缝合服装领子的问题解决方案探寻
  • ¥15 请问怎么才能复现这样的图呀