weixin_33698823 2013-11-27 06:04 采纳率: 0%
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AJAX数据查找不起作用

I have these codes

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
        <title>Display data in textboxes</title>
<style type="text/css"><!-- Style Sheet part start -->
html {
    overflow:auto;
}
body {
    background-color:#FFFFFF;
    margin:0 auto;
}
#mypopup
{
    float: left;
    width: 250px; height: 350px;
    background-color:#d5eef4 ;
    border: 1px solid #069;
    text-align:center;
    padding:2px;
    margin-top:150px;
    margin-left:100px;
    overflow:auto;
}
#header
{
    background-color:#3399FF;
    background-position:left center;
    line-height:25px;
    font-size:22px;
    color:#FFFF33;
    font-weight:600;
    border-bottom:1px solid #6699CC;
    padding:10px;
}
</style> <!-- Style Sheet part end -->
</head>
<body>
    <center>
        <div id="mypopup">
            <div id="header">Search Data</div>
                <div style="margin-top:80px;">
                    <form name="form1" action="#" method="post">
                        <table border=0; cellpadding="1" cellspacing="1" bgcolor="#CCFFFF" align="center" >
                            <tr>
                                <th>Code</th>
                                <th width="50px"><input type="text" name="txtsno" id="txtsno" value="" title="Enter product code" /></th>
                            </tr>
                            <tr>
                                <td>Product</td>
                                <td><input type="text" name="txtpro" id="txtpro" value="" title="Enter product name" ></td>
                            </tr>

                        </table>

<input type="button" name="button1" value="Display" onclick="send();">
                        <input type="reset" name="button2" value="Clear" >
                    </form>
                </div>
            </div>
    </center>

<script type="text/javascript"><!-- Javascipt starts -->
var xmlhttp = new XMLHttpRequest();

function send(){
    var Pcode = document.getElementById("txtsno").value;
    xmlhttp.onreadystatechange=function(){
        if (xmlhttp.readyState==4 && xmlhttp.status==200){
            document.getElementById("txtpro").value = xmlhttp.responseText;
        }
    }
xmlhttp.open("POST","test2.php",true);
xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded");
xmlhttp.send("data="+Pcode);
}
</script><!-- Javascript end -->
</body>
</html>

and test.php has following codes

<?php
require_once("connect.php");
$code = $_POST['data'];
$record_check = "SELECT packing FROM test WHERE sno = '$code' ";
$result=mysqli_query($con, $record_check);
$row = mysqli_fetch_array($result);

if(!$row)
die ('No record Found');
else {
    $productValue = $row['packing'];
}
echo $productValue;
?>

When I press DISPLAY button then this data appears in txtpro

Notice: Undefined variable: code in C:\wamp\www\db\test2.php on line 5 No record Found

What I am doing wrong? Please help me

  • 写回答

1条回答 默认 最新

  • weixin_33713503 2013-11-27 06:17
    关注

    try this

    function send(){
        var Pcode = document.getElementById("txtsno").value;
        var parameters = "data="+Pcode;
        xmlhttp.onreadystatechange=function(){
            if (xmlhttp.readyState==4 && xmlhttp.status==200){
                document.getElementById("txtpro").value = xmlhttp.responseText;
            }
        }
        xmlhttp.open("POST","test2.php",true);
        xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded");
        xmlhttp.setRequestHeader("Content-length", parameters .length);
        xmlhttp.setRequestHeader("Connection", "close");
        xmlhttp.send(parameters);
    }
    

    also you can use encodeURIComponent for variables

    if(isset($_POST['data'])){
        $code = $_POST['data'];
        $record_check = "SELECT packing FROM test WHERE sno = '$code' ";
        $result=mysqli_query($con, $record_check);
        $row = mysqli_fetch_array($result);
    
        if(!$row)
            echo 'No record Found';
        else {
            echo $row['packing'];
        }
    }
    
    评论

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