weixin_33704234 2018-04-04 17:51 采纳率: 0%
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jQuery AJAX的最简单形式

How to send the simplest form of jQuery AJAX request to the server every 60 seconds to keep the user status as ACTIVE while the page is still open.

There is no need to get any response back from the server:

setInterval(function() {
    $(document).load('path/to/keep-user-active.php');
}, 60000);

Then the PHP script will do the necessary.

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  • weixin_33674976 2018-04-04 17:57
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    Simple AJAX w/ JQuery. Note you don't have to do anything with the result but whatever you do want to do with it, put code where #div1 is.

    setInterval(function() 
    {
           $.ajax({url: "path/to/keep-user-active.php", success: function(result){
           $("#div1").html(result);
           }});
    }, 60000);
    
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