AJAX呼叫传回「未定义」

Question

AJAX call as follows:

$.get('file.php')
.done(function(data) {
    console.log(data);
});

Console returns:

[{"0":"PS001","code":"PS001"}]

However if amend the log to console.log(data.code) it returns undefined. Also, traversing JSON using each as such:

.done(function, data) {
    $.each(data, function(key, value) {
        console.log(value.code);
    });
)};

results in the following error:

[Error] TypeError: [{"0":"PS001","code":"PS001"}] is not a valid argument for
'in' (evaluating 'b-1 in a')

JSON looks well-formed, so not sure what the issue is?

Answer 1

Try this, because your code return json array.

console.log(data[0].code);  //If you getting JSON format

OR

console.log(JSON.parse(data)[0].code);  //If you getting JSON as String

Demo