为什么变量右移32位之后还是本身？

Question

int main() 
{
    int z = 0x12345678;
    cout << hex << z << endl;
    z = z >> 32;
    cout << hex << z << endl;

    return 0;
}

输出结果

Answer 1

32溢出了，相当于0
试试看31