要求是每个device code作为一组 根据日期取出每个code的最新的前10条
1条回答 默认 最新
- 淅雨听风 2020-10-09 21:03关注
SELECT a.*FROM
( SELECT
w.*,
(SELECT count(*) + 1
FROM weld_alarm WHERE weld_alarm.code = w.code AND weld_alarm.id < w.id ) AS group_id FROM weld_alarm w
) a WHERE a.group_id <= 20 order by code本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报