一道双向链表的题目,我按刘汝佳书上的写的,基本上和刘汝佳写的程序没什么区别,不一样的地方我认为我这样写也没错,但是不知道为什么评测时标程就AC,我写的就WA,有没有前辈愿意帮我看一下哪里出了问题?不胜感激!
标程
// UVa12657 Boxes in a Line
// Rujia Liu
#include<cstdio>
#include<algorithm>
using namespace std;
const int maxn = 100000 + 5;
int n, left[maxn], right[maxn];
inline void link(int L, int R) {
right[L] = R; left[R] = L;
}
int main() {
freopen("1.txt","r",stdin);
freopen("2.txt","w",stdout);
int m, kase = 0;
while(scanf("%d%d", &n, &m) == 2) {
for(int i = 1; i <= n; i++) {
left[i] = i-1;
right[i] = (i+1) % (n+1);
}
right[0] = 1; left[0] = n;
int op, X, Y, inv = 0;
while(m--) {
scanf("%d", &op);
if(op == 4) inv = !inv;
else {
scanf("%d%d", &X, &Y);
if(op == 3 && right[Y] == X) swap(X, Y);
if(op != 3 && inv) op = 3 - op;
if(op == 1 && X == left[Y]) continue;
if(op == 2 && X == right[Y]) continue;
int LX = left[X], RX = right[X], LY = left[Y], RY = right[Y];
if(op == 1) {
link(LX, RX); link(LY, X); link(X, Y);
}
else if(op == 2) {
link(LX, RX); link(Y, X); link(X, RY);
}
else if(op == 3) {
if(right[X] == Y) { link(LX, Y); link(Y, X); link(X, RY); }
else { link(LX, Y); link(Y, RX); link(LY, X); link(X, RY); }
}
}
}
int b = 0;
long long ans = 0;
for(int i = 1; i <= n; i++) {
b = right[b];
if(i % 2 == 1) ans += b;
}
if(inv && n % 2 == 0) ans = (long long)n*(n+1)/2 - ans;
printf("Case %d: %lld\n", ++kase, ans);
}
return 0;
}
我的代码
//Boxes in a line-doubly linked list
#include<cstdio>
#include<algorithm>
using namespace std;
int left[100010],right[100010];
void linked(int l,int r){
right[l]=r;left[r]=l;
}
int main(){
int n,m,kase=0;
while (scanf("%d%d",&n,&m)==2){
for (int i=1;i<=n;i++){
left[i]=i-1;
right[i]=(i+1)%(n+1);//good deal
}
right[0]=1;left[0]=n;//notice!!!
int op,x,y,inv;
while (m--){
scanf("%d",&op);
if (op==4) inv=!inv;
else {
scanf("%d%d",&x,&y);
if (op==3&&right[y]==x) swap(x,y);//all are changed!!!
if (op!=3&&inv) op=3-op;
if (op==1&&x==left[y]) continue;
if (op==2&&x==right[y]) continue;
int lx=left[x],rx=right[x],ly=left[y],ry=right[y];
if (op==1){
linked(lx,rx);linked(ly,x);linked(x,y);
}
else if (op==2){
linked(lx,rx);linked(y,x);linked(x,ry);//here is wrongTUT
}
else if (op==3){
if (right[x]==y){
linked(lx,y);linked(y,x);linked(x,ry);
}
else {
linked(ly,x);linked(x,ry);linked(lx,y);linked(y,rx);
}
}
}
}
int b=0;
long long ans=0;
for (int i=1;i<=n;i++){
b=right[b];
if (i%2==1) ans+=b;
}
if (inv&&n%2==0) ans=(long long)n*(n+1)/2-ans;
printf("Case %d: %lld\n",++kase,ans);
}
return 0;
}
谢谢各位前辈了!