insert语句在pl/sql中替换数据可以执行,但是java中却报错

java语句:
public int initiating(String title, String content, String numberLimit,String fkCustomerId) {
String pkId = "44";
String sql="insert into ACTIVITY_INFO (pk_id,title,content,fk_customer_id,number_limit,create_date) values(:pkId,:title,:content,:fkCustomerId,:numberLimit,sysdate)";
Query query = this.getSession().createQuery(sql);
query.setParameter("pkId", pkId);
query.setParameter("title", title);
query.setParameter("content", content);
query.setParameter("fkCustomerId", fkCustomerId);
query.setParameter("numberLimit", numberLimit);
int num = query.executeUpdate();
return num;
}
报错信息:
严重: Servlet.service() for servlet [springMvc] in context with path [/CREOAMS] threw exception [Request processing failed; nested exception is org.hibernate.hql.ast.QuerySyntaxException: unexpected token: values near line 1, column 89 [insert into ACTIVITY_INFO (pk_id,title,content,fk_customer_id,number_limit,create_date) values(:pkId,:title,:content,:fkCustomerId,:numberLimit,sysdate)]] with root cause
org.hibernate.hql.ast.QuerySyntaxException: unexpected token: values near line 1, column 89 [insert into ACTIVITY_INFO (pk_id,title,content,fk_customer_id,number_limit,create_date) values(:pkId,:title,:content,:fkCustomerId,:numberLimit,sysdate)]
at org.hibernate.hql.ast.QuerySyntaxException.convert(QuerySyntaxException.java:54)

1个回答


Query query = this.getSession().createQuery(sql);//HQL语句不能这么写,直接用save就完了。
使用

Query query = this.getSession().createSQLQuery(sql);
qq_29432727
qq_29432727 多谢大神指点,确实那个地方疏忽了
4 年多之前 回复
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