Android调用.net写的webservice_course

碰到一个调用webservice的问题，希望高手指点： 用Ksoap调用.net写的webservice时，需要post数据给webservice 但是数据格式里面不是单一的数据组合，而是有包含二维的

.NET调用WebService中数据类型问题，如decimal和DateTime不可用？_course

在做一个项目，涉及到与ERP系统进行集成，使用到WebService，ERP系统发布了一个WebService服务，在.NET中引用了，但生成的服务中，对于decimal和DateTime不能用，看了

Sqlite datetime类型如何存取，什么类型取出可以在android对其进行格式操作 _course

创建表： db.execSQL("create table if not exists test_time" + "(_id INTEGER PRIMARY KEY AUTOINCREMENT, " + "name VARCHAR, age Datetime)"); 插入数据： ContentValues cv=new ContentValues(); cv.put("name", "Ben"); cv.put("age", "2015-02-01"); db.insert("test_time", null, cv); cv.clear(); cv.put("name", "David"); cv.put("age", "2015-04-01"); db.insert("test_time", null, cv); Log.i("msg", "succee"); db.close(); 已经成功插入。 取数据： Cursor c=db.rawQuery("select name,age,strftime('%m',age) from test_time order by age asc",null); while(c.moveToNext()){ map=new HashMap<String,String>(); String user_name=c.getString(c.getColumnIndex("name")); String age=c.getString(c.getColumnIndex("strftime('%m',age)")); Log.v("age", age); String user_age=c.getString(c.getColumnIndex("age")); map.put("name",user_name); map.put("age",user_age); listItem.add(map); } db.close(); 这里出错报空指针异常 Log.v("age", age);

C# 反射DateTime，无法找到DateTime_course

Assembly system = Assembly.Load("System, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089"); Type t = system.GetType("DateTime"); 为什么反射不到DateTime，我怀疑是因为DateTime是struct类型而非class，如果是的话，如何反射struct类型，我是先获取Assembly，再在里面找Type，所以不要回答用typeof(DateTime)来获取Type

Convert.ToDateTime()时间格式_course

Convert.ToDateTime()时间后面怎么加上23:59:59.000 最近做一个查询，需要精确到时分秒，但是我去前台选定的时间： ``` DateTime jssj = Convert.ToDateTime(this.jssj.Value); ``` 获取的结束时间是：2019-03-31 00:00:00.000 怎么把 2019-03-31 00:00:00.000 后面的 00:00:00.000 改成23:59:59.000 源代码如下： ``` DateTime kssj = Convert.ToDateTime(this.kssj.Value); DateTime jssj = Convert.ToDateTime(this.jssj.Value); DateTime kssjjy = kssj.AddDays(-1); DateTime jssjjy = jssj.AddDays(1); ```

android sqlite 获得当天有效的行_course

public Cursor getRowsBetweenDate(Date startAt, Date endAt) { String selection = KEY_START_AT + " >= time('now', 'localtime') AND " + KEY_END_AT + " <= time('now', 'localtime')"; return sqLiteDatabase.query(TABLE_NAME, null, selection, null, null, null, null); } 我想获取全天有效的行，不是只有现在有效的行。我想获取这几天有效的所有的行。时间是从 00:00 到23:59:59。 如何实现？

Datetime作为数组并转换日期格式并插入数据库_course

<div class="post-text" itemprop="text"> <p>I'm importing data from CSV file into database through HTML form, having multiple datetime in format <code>23/06/2015 12:00</code> which i convert to <code>2015-23-06</code> with follwing code</p> <pre><code>$Datetime = $emapData['1']; //Format is 23/06/2015 12:00 $ConvertDatetime = DateTime::createFromFormat('d/m/Y', $Datetime); $NewDatetime = new DateTime($ConvertDatetime); $NewDate = $NewDatetime-&gt;format('Y-m-d'); Here I have date in desire format (2015-06-23) $NewTime = $NewDatetime-&gt;format('H:i'); Here I have time in format (7:00) </code></pre> <p>One solution is that i repeat above code by changing variables name to convert other datetime in csv which i did and things working fine but I'm thinking to use arrays, load the datetime into arrays and then convert datetime and then insert converted datetime into database.</p> <pre><code>$DateTimeArray = array( '2/17/2015 13:59', '2/20/2015 18:59', '2/05/2015 05:59', '2/15/2015 03:59', '2/19/2015 12:59', '2/10/2015 14:59' ); </code></pre> <p>and then foreach</p> <pre><code>foreach ($DateTimeArray as $DateTime){ $ConvertDatetime = DateTime::createFromFormat('m/d/Y', $DateTime); $NewDatetime = new DateTime($ConvertDatetime); $NewDate = $NewDatetime-&gt;format('Y-m-d'); $NewTime = $NewDatetime-&gt;format('H:i'); $ConvertedDateTime = $NewDate . " " . $NewTime; $FinalDateTime[] = $ConvertedDateTime; } print_r($FinalDateTime); </code></pre> <p>but the ouput is just this current datetime</p> <pre><code>Array ( [0] =&gt; 2015-07-23 20:44 [1] =&gt; 2015-07-23 20:44 [2] =&gt; 2015-07-23 20:44 [3] =&gt; 2015-07-23 20:44 [4] =&gt; 2015-07-23 20:44 [5] =&gt; 2015-07-23 20:44 ) </code></pre> <p>need help to sort it out.</p> </div>

格式未知时创建PHP DateTime_course

<div class="post-text" itemprop="text"> <p>With the help of <a href="https://stackoverflow.com/questions/23422915/create-date-time-when-the-format-is-unknown">this question</a>, I have been able to parse a date string into a <code>DateTime</code> object, then display it in the desired format. The <code>DateTime</code> constructor works well in deciphering <code>DateTime</code> strings with one (very understandable) exception - it cannot tell the difference between <code>dd/mm/YYYY</code> and <code>mm/dd/YYYY</code>.</p> <p>If I do the following:</p> <pre><code>$dt = new DateTime("05/03/1900"); // 5th march 1900 echo $dt-&gt;format('Y-m-d'); </code></pre> <p>Then I get the following output:</p> <pre><code>1900-05-03 </code></pre> <p>However, the original date is in <code>dd/mm/YYYY</code> format, so my output is incorrect - I now have the <code>3rd May 1900</code>.</p> <p>Is there a way to set <code>DateTime</code> to prefer <code>dd/mm/YYYY</code> over <code>mm/dd/YYYY</code> when parsing a date string?</p> <p><em>Edit:</em> I am calling <code>date_default_timezone_set('Europe/London');</code> in the constructor of this class but this doesn't seem to have any effect. Perhaps this isn't linked to the <code>DateTime</code> class.</p> </div>

Datetime转换为类对象中的字符串_course

<div class="post-text" itemprop="text"> <p>I know there are a lot open topics for this question but I wasn't able to find any solution.</p> <p>I am trying to get my object of class from entity in symfony via getter and I have trouble getting datetime field because it can not be converted to string. </p> <pre><code>$date = new \DateTime(); $get-&gt;getBirthDate(\DateTime::createFromFormat('Y-m-d', $date)), </code></pre> <p>I think this is proper way but it does not work. </p> <p>This code works:</p> <pre><code>$get-&gt;getBirthDate = $date-&gt;format('Y-m-d'), </code></pre> <p>but </p> <blockquote> <p>object of class declared dynamically</p> </blockquote> </div>

无法将DateTime对象保存到MySQL中的datetime字段_course

<div class="post-text" itemprop="text"> <p>Here is my database schema for my MySQL database:</p> <pre><code>create table noticia ( id int, imagen varchar(255), fecha datetime, titulo varchar(255), url varchar(255), descripcion varchar(255), contenido text ) </code></pre> <p>I'm using RedBeanPHP as my ORM to save the information to a database. Here is where I'm scraping and parsing the dates to a <code>DateTime</code> object as per the <a href="http://nl3.php.net/manual/en/datetime.construct.php" rel="nofollow">documentation</a>.</p> <pre><code>foreach ($element-&gt;find('span.fechanoticia') as $fecha) { $tmp = str_replace("/", "-", $fecha-&gt;innertext); print_r($tmp); $dateFoo = new DateTime($tmp); echo $dateFoo-&gt;format('Y-m-d H:i:s'); $newItem-&gt;set_fechanoticia($dateFoo); } </code></pre> <p>The <code>$tmp</code> variable this value for example:</p> <pre><code>05-09-2012 </code></pre> <p>The <code>echo</code> call to format returns:</p> <pre><code>2012-09-05 00:00:00 </code></pre> <p>Everything is peachy, and working.</p> <p>However when I try to save it to the database using RedBeanPHP I get this error:</p> <blockquote> <p>Fatal error: Uncaught exception 'RedBean_Exception_Security' with message 'Invalid Bean: property fecha ' in C:\xampp\htdocs\blog-uvm b.php:4880 Stack trace: #0 C:\xampp\htdocs\blog-uvm b.php(5108): RedBean_OODB-&gt;check(Object(RedBean_OODBBean)) #1 C:\xampp\htdocs\blog-uvm b.php(5082): RedBean_OODB-&gt;storeBean(Object(RedBean_OODBBean)) #2 C:\xampp\htdocs\blog-uvm b.php(7005): RedBean_OODB-&gt;store(Object(RedBean_OODBBean)) #3 C:\xampp\htdocs\blog-uvm\index.php(60): RedBean_Facade::store(Object(RedBean_OODBBean)) #4 {main} thrown in C:\xampp\htdocs\blog-uvm b.php on line 4880</p> </blockquote> <p>Can RedBeanPHP not handle datetime objects? </p> </div>

日期时间操作 DateTime.Parse(DateTime.Now._course

日期时间操作 DateTime.Parse(DateTime.Now.Tostring("yyyy-MM-dd")).AddDays(-7).ToShortDateSstring(); 获取上一周时间 但是格式是2000/8/8 我想转成2000-8-8

更改时区时，DateTime时间戳不会更改_course

<div class="post-text" itemprop="text"> <p>Alright so basically, I am a little confused about how the timestamp works in DateTime in PHP. I wish to make two methods that convert from a local time to UTC and vice versa.</p> <p>I currently have this:</p> <pre><code>/** * @param \IPS\DateTime $utcDateTime The UTC datetime. * @param \DateTimeZone $timezone The timezone to convert the UTC time to. * @return \IPS\DateTime New datetime object in local datetime. * @throws \Exception when the UTC date is not in UTC format. (debugging purposes) */ public static function utcToLocal($utcDateTime, $timezone) { if ($utcDateTime-&gt;getTimezone()-&gt;getName() !== "UTC") { throw new \Exception("Date time is not UTC!"); } $time = new DateTime($utcDateTime, new \DateTimeZone("UTC")); $time-&gt;setTimezone($timezone); return $time; } /** * @param \IPS\DateTime $localDateTime A datetime configured with the the user's timezone * @return DateTime New datetime object in UTC format * @throws \Exception When given datetime is already in UTC (for debugging purposes) */ public static function localToUtc($localDateTime) { if ($localDateTime-&gt;getTimezone()-&gt;getName() === "UTC") { throw new \Exception("Value is already UTC"); } $time = new DateTime($localDateTime, $localDateTime-&gt;getTimezone()); $time-&gt;setTimezone(new \DateTimeZone("UTC")); return $time; } </code></pre> <p>When I debug this code, at the last line <code>return $time</code> in <code>localToUtc(...)</code> my debugger shows the correct conversions: <a href="https://i.stack.imgur.com/fJXaZ.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/fJXaZ.png" alt="Debugger showing correct times"></a></p> <p>However, when I evaluate the expression </p> <p><code>$localDateTime-&gt;getTimestamp() === $time-&gt;getTimestamp()</code> </p> <p>it will return true.</p> <p>So I am a little confused, I just want the timestamps to change when I change the timezone. I am thinking maybe I need to work with <code>getOffset()</code> but I want to make sure I do it in the correct way. I'd also prefer not to use any string format tricks because I feel like that is not the correct way.</p> </div>

PHP将本地时间转换为UTC DateTime_course

<div class="post-text" itemprop="text"> <p>I want to convert my local timezone dateTime to UTC timezone DateTime.</p> <pre><code>date_default_timezone_set('Asia/Calcutta'); $datetime = "2016-05-05 18:33:00"; echo date_default_timezone_get()."&lt;br&gt;"; // Asia/Calcutta date_default_timezone_set('UTC'); echo date_default_timezone_get()."&lt;br&gt;"; //UTC echo $utcDateTime = date("Y-m-d H:i:s",strtotime($datetime)); </code></pre> <p><strong>Current Output</strong></p> <pre><code>2016-05-05 18:33:00 </code></pre> <p>But, Problem is do not convert local dateTime to UTC dateTime. It will give output as Local DateTime.</p> </div>

DateTime错误的时间_course

<div class="post-text" itemprop="text"> <p>I am creating notifications system and here is a task: get the time, when a notification was sent. I mean the following: 1 minute ago, 13 hours ago and so on. I have already made up a script but it shows wrong time. For example instead of showing '5 minutes ago' it shows '9 hours ago'. Here is the alrogithm:</p> <ol> <li>Get old timestamp from database. Old timestamp is the time, when a notification was sent.</li> <li>Get current users timestamp.</li> <li>Get difference between them.</li> <li>Echo result.</li> </ol> <p>Here is the PHP code:</p> <pre><code>$fromdb = '1503737539'; //For this example think, that this variable is from database. //This timestamp was created 5 minutes earlier, so in result it should show '5 minutes ago'. $curr = new DateTime(); $got2 = new DateTime(date('Y-m-d H:i:s',$fromdb)); $interval = $curr-&gt;diff($got2); echo $interval-&gt;format('%d')." days ".$interval-&gt;format('%h')." Hours ".$interval-&gt;format('%i')." Minutes ".$interval-&gt;format('%s')." Seconds"; </code></pre> <p>The output is: </p> <blockquote> <p>0 days 9 hours ....</p> </blockquote> <p>instead of </p> <blockquote> <p>0 days 0 hours 5 minutes ....</p> </blockquote> <p>How can I fix that? I guess that this is a problem with timezones. But how can I guess guests timezone though? </p> <p>Update: Change code: $got2 = new DateTime(date('Y-m-d H:i:s',$fromdb));</p> <p>And interesting fact: The more is actual difference, the less time it shows in output. For example: Old timestamp was created at 8:00 am, and current is 15:00 pm, it shows 0 days 1 hour in output.</p> </div>

DateTime diff返回错误的值_course

<div class="post-text" itemprop="text"> <p>I would like to return the number of days between NOW and some datetime using DateTime object. My dates are:</p> <pre><code>$now = "2018-03-08 14:00:00"; $last = "2018-02-06 20:00:00"; </code></pre> <p>And I do it like this:</p> <pre><code>$now = new DateTime(); $last_dt = new DateTime($last); $difference = $last_dt-&gt;diff($now); $difference-&gt;format('%d'); $num_of_days = $difference-&gt;d; </code></pre> <p>For some weird reason, the value of $num_of_days is 1 (instead of like 30)</p> <p>Anybody knows why please?</p> <p>Thank you</p> </div>

找不到DateTime类，即使添加反斜杠也是如此_course

<div class="post-text" itemprop="text"> <p>I'm trying to use DateTime to measure the time it takes for a part of a program to run.</p> <p>My code is in the namespace 'App'. From my understanding, DateTime is in the global namespace, so it has to be prefixed with a blacklash. Which I've done, but I'm still getting an error that DateTime class can't be found.</p> <pre><code>$startTime= new \DateTime(date('H:i:s')); //other code in here $endTime = new \DateTime(date('H:i:s')); $timeTaken = date_diff($startTime, $endTime)-&gt;format('%H:%i:%s'); </code></pre> <p>When I run this I get the following error:</p> <pre><code> Class 'App\DateTime' not found </code></pre> <p>Any ideas how I can resolve this?</p> </div>

C#.net datetime类型转换失败_course

表中有一个datetime对象，定义了一个datatimepicker，但是总是提示类型转换失败， ``` try { Course.conn.Open(); SqlCommand cmd = new SqlCommand("insert into Student values('"+textBox2.Text+"','"+textBox3.Text+"','"+textBox4.Text+"','"+textBox5.Text+"','"+DateTime.Parse(dateTimePicker1.Text)+"','"+textBox6.Text+"','"+textBox7.Text+"','"+DateTime.Parse(dateTimePicker2.Text)+"','"+textBox8.Text+"')",Course.conn); cmd.ExecuteNonQuery();//执行 MessageBox.Show("添加成功！"); } ``` 调用这个DateTime.Parse(dateTimePicker1.Text)出错，求大神解答

DateTime需要为空时，如何插入值？_course

SQL Server中，DateTime可以为null，而C#中不可以。 属性类型我写为DateTime？，有添加和修改功能需要用到这个字段 在Ajax层获取页面数据时，我加了判断，如果获得的字符串长度为0，则值为null。否则获取字符串并转成DateTime类型。 在数据访问层中，我判断，如果获得的属性值为null那么在SQL语句中不添加此属性的参数，否则添加。 但是在运行时，不管有没有值，都会提示找不到方法:“Void Model层命名空间.Model类.set_属性名(System.DateTime)”。"}

python3的datetime无法相减_course

import datetime date1 = datetime.datetime(2019, 6, 1) date2 = datetime.datetime.now().strftime("%y-%m-%d %H:%M:%S") print(date2-date1) 提示：TypeError: unsupported operand type(s) for -: 'str' and 'str'

datetime-local输入没有显示值？_course

<div class="post-text" itemprop="text"> <p>I am trying to create a simple HTML form and the one element must capture the date and time, I am currently using:</p> <pre><code> &lt;input type="datetime-local" id="early" name="early" value="02/15/15T03:35"&gt; </code></pre> <p>However the issue is that it does not seem to populate the value of the element and just shows the normal blank values?</p> <p>My format that datetime-local seems to show on Chrome is dd/mm/Y, --:-- (presumably hours:minutes)</p> <p>Any help is appreciated as to the correct format?</p> <p>Thanks!</p> </div>

如何将PHP DateTime序列化为JavaScript DateTime？_course

<div class="post-text" itemprop="text"> <p>I am using the <a href="http://symfony.com/doc/current/components/serializer.html" rel="nofollow">Symfony Serializer Component</a> to serialize some PHP objects to JSON. Among them are DateTime objects.</p> <p>The JSON output I get for a PHP DateTime object is as follows:</p> <pre><code>{ "lastErrors" : { "warning_count" : 0, "warnings" : [], "error_count" : 0, "errors" : [] }, "timezone" : { "name" : "UTC", "location" : { "country_code" : "??", "latitude" : 0, "longitude" : 0, "comments" : "" } }, "offset" : 0, "timestamp" : 1416903372 } </code></pre> <p>To actually work with this object I need to convert the timestamp to a JS DateTime object. Also this will probably fail on some machines when the 32-bit timestap overflows in a few years.</p> <p>How can I make the Symfony Serializer output PHP DateTime objects as JavaScript DateTime objects?</p> </div>

数据分析三剑客精讲+实战_course

它们是极为流行的数据分析利器，是人工智能和大数据领域必备技能。NumPy专注于科学计算，Matplotlib专注于数据可视化，Pandas专注于数据分析。 本专题通过引入案例，按照数据分析开发流程，全面讲解数据分析的重点知识。采用行业数据集，并通过实际项目让学员快速掌握数据分析的核心技能和项目技巧。