fiter可以过滤jsp等后缀的url,但就是过滤不了.do请求，fiter该怎么写 求帮忙

Question

/*public void doFilter(ServletRequest arg0, ServletResponse arg1,
        FilterChain arg2) throws IOException, ServletException {
    // 获得在下面代码中要用的request,response,session对象
    log.info(".....ThirdPartyStoresFilter...doFilter.....");    
    HttpServletRequest servletRequest = (HttpServletRequest) arg0;
    HttpServletResponse servletResponse = (HttpServletResponse) arg1;
    HttpSession session = servletRequest.getSession();
    String  user =(String) session.getAttribute("username");
    // 获得用户请求的URI
    String path = servletRequest.getRequestURI();
    System.out.println(servletRequest.getRequestURL()+"(00000000");
    // 登陆页面无需过滤
    if (path.indexOf("/login.jsp") > -1 || path.indexOf("/images") > -1
            || path.indexOf("/js") > -1 || path.indexOf("/style") > -1) {
        arg2.doFilter(arg0, arg1);
        return;
    }

    //得到上下文路径
    String returnUrl = servletRequest.getContextPath();
    try {

        // 判断如果没有取到员工信息,就跳转到登陆页面
        if (StringUtils.isBlank(user)) {
            // 跳转到登陆页面
            servletResponse.sendRedirect(returnUrl
                    + "/shop/login.jsp");
        } else {
            // 已经登陆,继续此次请求
            arg2.doFilter(arg0, arg1);
        }
    } catch (Exception e) {
        servletResponse.sendRedirect(returnUrl
                + "/shop/login.jsp");
    }
}
<filter>
    <filter-name>filter</filter-name>
    <filter-class>...</filter-class> 
</filter>
<filter-mapping>
    <filter-name>filter</filter-name>
    <url-pattern>/shop/*</url-pattern>
    </filter-mapping>
*/

Answer 1

你是不是还用了 struts啊？ .do 请求应该是被它给拦截了