Spring Security 4.0 CAS实现单点登录 &server参数问题

Question

cas 中已经设置参数

 <bean id="casProcessingFilterEntryPoint" class="org.springframework.security.ui.cas.CasProcessingFilterEntryPoint" autowire="default" dependency-check="default" lazy-init="default">
<property name="loginUrl" value="http://locahost:8088/sso/login?sysname=Pentaho%20TEST"/>  <!--设置系统名称(参数)-->
<property name="serviceProperties">
<ref local="serviceProperties"/>
</property>
</bean>

跳转时设置

 <bean id="serviceProperties" class="org.springframework.security.ui.cas.ServiceProperties" autowire="default" dependency-check="default" lazy-init="default">
<property name="service" value="http://localhost:8080/pentaho/j_spring_cas_security_check"/>
<property name="sendRenew" value="true"/>
</bean>

跳转后得到的 url 是
http://locahost:8088/sso/login?sysname=Pentaho%20TEST?server=http%3A%2F%2Flocalhost%3A8080%2Fpentaho%2Fj_spring_cas_security_check
需得到的 url 是
http://locahost:8088/sso/login?sysname=Pentaho%20TEST&server=http%3A%2F%2Flocalhost%3A8080%2Fpentaho%2Fj_spring_cas_security_check
该如何设置？设置哪个参数？
即 ?server 变为 &server

Answer 1

cas sso单点登录系列3_cas-server端配置认证方式实践(数据源+自定义java类认证)
https://www.cnblogs.com/wangyang108/p/5843923.html