解析json字符串 取出value值

Question

我用JSON.stringify()方式把数据转换成json字符串，请问大神怎么把desc的值取出来
var obj={"desc":"my_test.department","child":[{"desc":"name2(string)","child":[]},{"desc":"count2(int)","child":[]}]};

Answer 1

JS:
父对象的desc获取 : var fatherDesc = obj.desc;
对象的desc获取: var childs=obj.child;
childs.forEach(function(e){

alert(e.desc);
})

Answer 2

你用什么语言？？？？？？

Answer 3

使用“对象.字段”格式取

Answer 4

var obj={"desc":"my_test.department","child":[{"desc":"name2(string)","child":[]},{"desc":"count2(int)","child":[]}]};
var obj2 = eval(obj);
alert(obj2.child[0].desc);