ACM里面的超时问题（困惑）

acm中time limit包不包括编译时间？还是指的是运行时间限制？？？？？？

1个回答

T_world 回复qq_36212394: ACM的题目一般的时间限制都是1S，一般要求算法优化到O(n)或者O(nlogn)，当然O(n^2)有时候也是可以的，但是会很危险，有可能擦着边过

C++或者是Java运行超时，怎么解决这个问题，我已经改变了好几个思路都不行，除了改变思路还有什么可以解决这个问题？
c语言 ACM上的现实超时了应该怎么改
#include "stdio.h" #include "conio.h" int main() { int day,month,year,sum,leap; while(scanf("%d %d %d",&year,&month,&day)!=EOF) { switch(month)//先计算某月以前月份的天数 { case 1: sum=0;break; case 2: sum=31;break; case 3: sum=59;break; case 4: sum=90;break; case 5: sum=120;break; case 6: sum=151;break; case 7: sum=181;break; case 8: sum=212;break; case 9: sum=243;break; case 10: sum=273;break; case 11: sum=304;break; case 12: sum=334;break; default: break; } sum = sum + day; if( year%400==0 || (year%4==0 && year%100==0) ) leap =1; else leap =0; if(leap ==1 && month>2) sum++; printf("%d\n",sum); } }
The Team of ACM/ICPC
Problem Description There are 3 people in a team of ACM/ICPC. Every member of the team will occasionally make some mistakes in the contest. So Mr.F tests every one and everybody gets a Mistake Value x. If the Mistake Values of the 3 members of a team are respectively a, b, c, then the Mistake Value of the team is m = min{ |a-b|, |b-c|, |c-a| }. Your job is to find the best plan to minimize M which is the sum of all the Mistake Value of teams. Input In the first line, there are two integers N and K. N is the number of people who will make teams and K is the number of teams which is supposed to make. (3<= N <=100000) (0<= k <= N/3 ) There are N lines followed. Each line has an integer D, which is the Mistake Value of the person.(0<=D<=1000000000) Output Print the minimal M in one line. Sample Input 7 2 1 5 3 2 4 7 9 Sample Output 2

Problem Description 输入一个英文句子，将每个单词的第一个字母改成大写字母。 Input 输入数据包含多个测试实例，每个测试实例是一个长度不超过100的英文句子，占一行。 Output 请输出按照要求改写后的英文句子。 Sample Input i like acm i want to get an accepted Sample Output I Like Acm I Want To Get An Accepted

ACM是一种什么样的体验

Bus Schedules 巴士调度的问题
Problem Description The Association of Commuters in Montreal (ACM) wishes to create a website for the city’s publictransit commuters, in order to promote public transit. A prominent reason for people to drive to work instead of commuting is the time wasted on the subway and buses. For this reason, the ACM wishes to add a form on their website so that visitors will be able to specify two points on the island, and the website will find the quickest route between those two points using its database of subway and bus schedules. Seeing how this may help improve the environment and the greenhouse effect, you offer your help. Input The first line of each test case will contain a positive integer n, the number of bus and subway schedules which will follow. Each schedule will begin with a line containing a positive integer m, the number of stops along the path. m lines will follow, describing the stops of the day in chronological order. Each stop will begin by a time in the format hh : mm, between 00 : 00 and 23 : 59 inclusively. There will be at least one minute between each stop — in other words, all the stop times for a particular bus will be different. A single space will follow, and the rest of the line will contain a name describing the stop. The name will not contain spaces nor capital letters, and will be at most 20 characters long. Stops with the same name obviously denote the same physical location, where passengers can wait for other buses or subways to stop. After the day completes, the buses and subways mysteriously disappear and reappear at some point before their first stop. They cannot carry any passengers at that time, so the passengers must spend the night waiting at some stop.Each schedule repeats itself every day. After the schedules, a line will contain a time and two locations of at most 20 characters, the start and the goal. Output the minimum number of minutes needed for a passenger at the start location at the given time to reach the goal location. He is able to enter any bus which stops at his start location at the given starting time or later, and he can also switch from a bus to another instantaneously if they happen to stop at the same place at the same time. He can also wait at a stop for an arbitrary amount of time. Output If the destination cannot be reached, output “impossible”. The last line of the input will contain the integer 0 and should not be processed. All the numbers in the input will be at most 1000. Sample Input 2 4 00:01 loc_a 00:02 loc_b 00:10 loc_c 00:20 loc_a 2 00:02 loc_b 00:04 loc_c 00:00 loc_a loc_c 1 3 00:00 foo 01:00 bar 02:00 baz 01:30 bar foo 1 4 00:00 baz 01:00 foo 02:00 bar 03:00 baz 02:30 bar foo 0 Sample Output 4 impossible 2790
Line & Circle Maze 迷宫的问题
Problem Description A deranged algorithms professor has devised a terrible final exam: he throws his students into a strange maze formed entirely of linear and circular paths, with line segment endpoints and object intersections forming the junctions of the maze. The professor gives his students a map of the maze and a fixed amount of time to find the exit before he floods the maze with xerobiton particles, causing anyone still in the maze to be immediately inverted at the quantum level. Students who escape pass the course; those who don't are trapped forever in a parallel universe where the grass is blue and the sky is green. The entrance and the exit are always at a junction as defined above. Knowing that clever ACM programming students will always follow the shortest possible path between two junctions, he chooses the entrance and exit junctions so that the distance that they have to travel is as far as possible. That is, he examines all pairs of junctions that have a path between them, and selects a pair of junctions whose shortest path distance is the longest possible for the maze (which he rebuilds every semester, of course, as the motivation to cheat on this exam is very high). The joy he derives from quantumly inverting the majority of his students is marred by the tedium of computing the length of the longest of the shortest paths (he needs this to know to decide how much time to put on the clock), so he wants you to write a program to do it for him. He already has a program that generates the mazes, essentially just a random collection of line segments and circles. Your job is to take that collection of line segments and circles, determine the shortest paths between all the distinct pairs of junctions, and report the length of the longest one. The input to your program is the output of the program that generates his mazes. That program was written by another student, much like yourself, and it meets a few of the professor's specifications: 1) No endpoint of a line segment will lie on a circle; 2)No line segment will intersect a circle at a tangent; 3) If two circles intersect, they intersect at exactly two distinct points; 4)Every maze contains at least two junctions; that is, a minimum maze is either a single line segment, or two circles that intersect. There is, however, one bug in the program. (He would like to have it fixed, but unfortunately the student who wrote the code never gave him the source, and is now forever trapped in a parallel universe.) That bug is that the maze is not always entirely connected. There might be line segments or circles, or both, off by themselves that intersect nothing, or even little "submazes" composed of intersecting line segments and circles that as a whole are not connected to the rest of the maze. The professor insists that your solution account for this! The length that you report must be for a path between connected junctions! Example: 1.2. 3.4. Detail Description: Pictrue 1: Line segments only. The large dots are the junction pair whose shortest path is the longest possible. Pictrue 2: An example using circles only. Note that in this case there is also another pair of junctions with the same length longest possible shortest path. Pictrue 3: Disconnected components. Pictrue 4: Now the line segments are connected by a circle, allowing for a longer shortest path. Input An input test case is a collection of line segments and circles. A line segment is specified as "L X1 Y1 X2 Y2" where "L" is a literal character, and (X1,Y1) and (X2,Y2) are the line segment endpoints. A circle is specified by "C X Y R" where "C" is a literal character, (X,Y) is the center of the circle, and R is its radius. All input values are integers, and line segment and circle objects are entirely contained in the first quadrant within the box defined by (0,0) at the lower left and (100,100) at the upper right. Each test case will consist of from 1 to 20 objects, terminated by a line containing only a single asterisk. Following the final test case, a line containing only a single asterisk marks the end of the input. Output For each input maze, output "Case N: ", where N is the input case number starting at one (1), followed by the length, rounded to one decimal, of the longest possible shortest path between a pair of connected junctions. Sample Input L 10 0 50 40 L 10 4 0 50 0 L 10 1 0 60 1 0 L 0 30 50 30 * C 25 2 5 25 C 50 2 5 25 C 25 5 0 25 C 50 5 0 25 * L 0 0 80 80 L 80 1 00 100 80 * L 0 0 80 80 L 80 1 00 100 80 C 85 8 5 10 * * Sample Output Ca se 1: 68.3 Ca se 2: 78.5 Ca se 3: 113.1 Ca se 4: 140.8
ACM 在线评测系统怎么计算程序运行时间和占用内存？
ACM 在线评测系统怎么计算程序运行时间和占用内存？ 总是会被超时困扰，要怎么去考虑程序到底会不会超时
Simulation? 模拟的问题
Problem Description A computer simulation, a computer model, or a computational model is a computer program, or network of computers, that attempts to simulate an abstract model of a particular system. Computer simulations have become a useful part of mathematical modeling of many natural systems in physics, astrophysics, chemistry and biology, human systems in economics, psychology, social science, and engineering, of course, also computer. “Fundamentals of compiling” is an important course for computer science students. In this course, most of us are asked to write a compiler to simulate how a programming language executes. Today, boring iSea invites a new programming language, whose name is Abnormal Cute Micro (ACM) language, and, YOU are assigned the task to write a compiler for it. ACM language only contains two kinds of variables and a few kinds of operations or functions, and here are some BNF-like rules for ACM. Also, here is some explanation for these rules: 1) In ACM expressions, use exactly one blank to separate variables and operators, and as the rule indicates, the operator should apply right to left, for example, the result of “1 - 2 - 3" should be 2. 2) In the build function, use exactly one blank to separate integers, too. 3) Beside there are brackets in function, no other bracket exists. 4) All the variables are conformable, and never exceed 10000. Given an ACM expression, your task is output its value. If the result is a integer, just report it, otherwise report an array using the format “{integer_0, integer_1, … , integer_n}”. Input The first line contains a single integer T, indicating the number of test cases. Each test case includes a string indicating an valid ACM expression you have to process. Technical Specification 1. 1 <= T <= 100 2. 1 <= |S| <= 100, |S| indicating the length of the string. Output For each test case, output the case number first, then the result variable. Sample Input 10 1 + 1 1 - 2 - 3 dance(3) vary(2) * 2 vary(sum(dance(5) - 1)) dance(dance(-3)) 1 - 2 - 3 * vary(dull(build(1 2 3))) dance(dance(dance(dance(dance(2))))) sum(vary(100)) - sum(build(3038)) build(sum(vary(2)) dull(build(1 0)) 2 dull(dance(2))) - build(1 1 1 1) Sample Output Case 1: 2 Case 2: 2 Case 3: {3, -2, 1} Case 4: {2, 4} Case 5: {2, 1} Case 6: -4 Case 7: {2, 5} Case 8: {4, -3, 2, -1} Case 9: 2012 Case 10: {2, 0, 1, 2}
C++新人 遇到一道ACM的题 不知问题出在哪里

ACM
alsomagic often has unexpected gains from his strolling around. One day, he found a magical machine, on which there was an expression "Automatic Card-interpret Machine (ACM)-TYPE N". Oh.....it was a machine used to read cards. beside of the ACM, there were a great many cards labeled 0, 1, 2 ... alsomagic counted it again and again, then found the total of them is 2^N...oh, good heavens! What were they used to do? Piquant alsomagic was so curious that he put a card with number k into ACM, but the machine showed that he must input the passwords! alsomagic had no idea. So he guest and try some number, wonder happened---he shoot it!!! A beautiful photo of a ppmm came out from the ACM... So pp ... alsomagic was very exited and he was so careful that he found some words on the screen:" The password of card k/2 + (k%2)*2^(N-1) is XXXXXX." By seeing these alsomagic put the card whose number is k/2 + (k%2)*2^(N-1) into ACM and another photo of ppmm appeared! And some other words were shown on the screen too:" The password of... " How many cards' password should poor alsomagic at least know if he wanted to see all of the photos? Input This problem consists of several test cases. Each case consists of exactly one line containing an integer N (0 < N <= 200), which indicates the ACM's type. A case with N = 0 means the end of test, which should not be proceeded. Output For each test case you should just output a single number perline. Sample Input 2 3 0 Sample Output 3 4
ACM题目 求思路 枚举超时·
God of Number Theory 思路问题
Problem Description In ACM_DIY, there is one master called “AekdyCoin”. As we know, he is the god of “Number Theory”. He always kills the problem about “Number Theory” in seconds! But of course we do not have any idea about these problems~ One day in ACM_DIY, AekdyCoin asks us one problem: You are given three non-negative integers A, B and K, you are expected to find how many X that satisfy. X^A = B( mod (2K + 1) ) X is in the ranger [0, 2K]; Of course we have no idea about this problem, so could you help us? Input The first line is one integer T indicates the number of the test cases. (T <= 1000) Then for every case, only one line contains three integers A, B and K. (1 <= A, B <= 10^9, 1 <= K <= 5 * 10^8) Output Output the answer in a single line. Sample Input 3 1 1 1 11 11 11 111 111 111 Sample Output 1 0 0

New Game 策略游戏算法
Problem Description While ZSTU’s acmers were coding, coach Yehr was so bored that he created a new game to kill time. And the game is called “Yehr Game” because of the inventer. Yehr Game is a board game involving two players. It is played on a board with 40 squares arranged in an ten-by-four grid. At the beginning of the game each player controls four pieces: one acm, one bahamas, one cab and one daze. If one player has no pieces to move, he lost the game. Setup: Yehr Game is played on a rectangle board of ten rows and four columns. The pieces are divided, by convention, into red and black sets. The players are referred to as "Red" and "Black", and each begins the game with four pieces of the specified color. These consist of one acm, one bahamas, one cab and one daze. Movement: First, they setup their pieces on the board. (1) the piece red acm can be placed on A1~,A2,A3,A4,A5;the piece black acm A6~A10; (2) the piece red bahamas can place on B1~B5; the piece black Bahamas B6~B10; (3) the piece red cab can place on C1~C5; the piece black cab C6~C10; (4) the piece red daze cab can place on D1~D5; the piece black daze D6~D10; Second, they determine who moves first by dice. After the initial move, the players alternately move one piece at a time. Each chess piece has its own style of moving. (1) Acm can only move one direction: red from left to right; black from right to left. Acm can only move to the next square. If one player’s acm moves to a square with the opponent acm, he win the game. (2) Bahamas and cab can move two direction: from left to right or from right to left. And they can move any number of squares but may not leap over other pieces. (3) Daze can only move one direction: red from right to left; black from left to right.Daze can only move to the next square. In order to win the game, every clever player places the red daze on d5 and the black on d6. Of Course, we assume that all players are clever. Input The input contains several test cases. Each test case contains three lines: First line contains one integer number 0 or 1: 0 indicated red move first and 1 black first. Second line contains four integer numbers r1, r2, r3, r4 indicating the four red pieces’ square. For example, r3=3 indicating the red cab on C3. Third line contains four integer numbers k1, k2, k3, k4 indicating the four black pieces’ square. For example, k1=9 indicating the black acm on A9. We assume that r4 is always 5, and K4 is 6. Output For each test case, if red win print Red in a single line, else print Black. Sample Input 0 4 5 5 5 7 6 6 6 Sample Output Red
Quicksum 求和的问题
Problem Description A checksum is an algorithm that scans a packet of data and returns a single number. The idea is that if the packet is changed, the checksum will also change, so checksums are often used for detecting transmission errors, validating document contents, and in many other situations where it is necessary to detect undesirable changes in data. For this problem, you will implement a checksum algorithm called Quicksum. A Quicksum packet allows only uppercase letters and spaces. It always begins and ends with an uppercase letter. Otherwise, spaces and letters can occur in any combination, including consecutive spaces. A Quicksum is the sum of the products of each character's position in the packet times the character's value. A space has a value of zero, while letters have a value equal to their position in the alphabet. So, A=1, B=2, etc., through Z=26. Here are example Quicksum calculations for the packets "ACM" and "MID CENTRAL": ACM: 1*1 + 2*3 + 3*13 = 46MID CENTRAL: 1*13 + 2*9 + 3*4 + 4*0 + 5*3 + 6*5 + 7*14 + 8*20 + 9*18 + 10*1 + 11*12 = 650 Input The input consists of one or more packets followed by a line containing only # that signals the end of the input. Each packet is on a line by itself, does not begin or end with a space, and contains from 1 to 255 characters. Output For each packet, output its Quicksum on a separate line in the output. Sample Input ACM MID CENTRAL REGIONAL PROGRAMMING CONTEST ACN A C M ABC BBC # Sample Output 46 650 4690 49 75 14 15

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