2017-02-12 16:45

Booklet Printing

Description

When printing out a document, normally the first page is printed first, then the second, then the third, and so on until the end. However, when creating a fold-over booklet, the order of printing must be altered. A fold-over booklet has four pages per sheet, with two on the front and two on the back. When you stack all the sheets in order, then fold the booklet in half, the pages appear in the correct order as in a regular book. For example, a 4-page booklet would print on 1 sheet of paper: the front will contain page 4 then page 1, and the back will contain page 2 then page 3.

Front Back

| | | | | |

| 4 | 1 | | 2 | 3 |

| | | | | |

Your task is to write a program that takes as input the number of pages to be printed, then generates the printing order.

Input

The input contains one or more test cases, followed by a line containing the number 0 that indicates the end of the file. Each test case consists of a positive integer n on a line by itself, where n is the number of pages to be printed; n will not exceed 100.
Output

For each test case, output a report indicating which pages should be printed on each sheet, exactly as shown in the example. If the desired number of pages does not completely fill up a sheet, then print the word Blank in place of a number. If the front or back of a sheet is entirely blank, do not generate output for that side of the sheet. Output must be in ascending order by sheet, front first, then back.
Sample Input

1
14
4
0
Sample Output

Printing order for 1 pages:
Sheet 1, front: Blank, 1
Printing order for 14 pages:
Sheet 1, front: Blank, 1
Sheet 1, back : 2, Blank
Sheet 2, front: 14, 3
Sheet 2, back : 4, 13
Sheet 3, front: 12, 5
Sheet 3, back : 6, 11
Sheet 4, front: 10, 7
Sheet 4, back : 8, 9
Printing order for 4 pages:
Sheet 1, front: 4, 1
Sheet 1, back : 2, 3

• 点赞
• 写回答
• 关注问题
• 收藏
• 邀请回答

2条回答默认 最新

• devmiao 2017-02-13 18:21
已采纳

#include
int s[500][4];
int main()
{
int P,i;
while (scanf("%d",&P)!=EOF)
{
if (P==0) return 0;
int N=(P-1)/4+1;
int M=4*N;
int l=1,r=M;
for (i=1;i<=N;i++)
{
s[i][0]=r--;
s[i][1]=l++;
s[i][2]=l++;
s[i][3]=r--;
}
printf("Printing order for %d pages:\n",P);
for (i=1;i<=N;i++)
{
if (!(s[i][0]>P && s[i][1]>P))
{
printf("Sheet %d, front:",i);
if (s[i][0]>P) printf(" Blank, ");
else printf(" %d, ",s[i][0]);
if (s[i][1]>P) printf("Blank\n");
else printf("%d\n",s[i][1]);
}
if (!(s[i][2]>P && s[i][3]>P))
{
printf("Sheet %d, back :",i);
if (s[i][2]>P) printf(" Blank, ");
else printf(" %d, ",s[i][2]);
if (s[i][3]>P) printf("Blank\n");
else printf("%d\n",s[i][3]);
}
}
}
return 0;
}

点赞 评论
• 不要装了哥 2017-02-13 01:18
``````#include<iostream>
using namespace std;

int dp[250025];
int v[100],num[100];
int max( int a,int b )
{
return a > b ? a : b;
}
int main()
{
int i,j,n,sum,cnt,k;
while(scanf("%d",&n),n>0)
{
cnt=0;
for(i=0;i<n;i++){ scanf("%d%d",&v[i],&num[i]);cnt+=v[i]*num[i];}
memset(dp,0,sizeof(dp));
sum=cnt/2;
for(i=0;i<n;i++)
for(j=0;j<num[i];j++)
for(k=sum;k>=v[i];k-=v[i])
dp[k]=max(dp[k],dp[k-v[i]]+v[i]);
if(cnt-dp[sum]>dp[sum])
printf("%d %d\n",cnt-dp[sum],dp[sum]);
else printf("%d %d\n",dp[sum],cnt-dp[sum]);
}
return 0;
}

</span>
``````
点赞 评论