java8 lambda 这个该怎么写

Question

有会用java8的 stream()写法吗. 实现下面这样的.

                String[] arrs = {"A", "B", "C", "D", "E", "F"};

        List<String> as = new LinkedList<>();
        List<String> bs = new LinkedList<>();
        int i = 0;
        for (String arr : arrs) {
            i++;
            if (i % 2 == 0) {
                as.add(arr);
            } else {
                bs.add(arr);
            }
        }

Answer 1

java的不会，C#的给你写一个，思路是将原始数据编号，然后根据编号的奇数偶数分组
C#写法

 string[] arrs = {"A", "B", "C", "D", "E", "F"};
var query = arrs.Select((x, i) => new {x , i}).GroupBy(x => x.i % 2).Select(x => x.Select(y => y.x).ToList()).ToArray();
var as = query[0];
var as = query[1];