我想要求出按照上级机构和年份为条件 查出每个单位总定编人数，关键岗位总人数，关键岗位总人数占总定编人数百分比，关键岗位总人数占总定编人数缺失数

缺失数 不理解，大概是这样的

postgres=# create table info(storey varchar(100),SUPERIOR varchar(100),year int,dingbian int,key bool,zaigang int,position varchar(100));
CREATE TABLE


insert into info values('一中','市教育局',2016,100,True,90,'教师');
insert into info values('一中','市教育局',2016,50,False,50,'会计');
insert into info values('二中','市教育局',2016,50,True,50,'教师');

postgres=# select * from info;
 storey | superior | year | dingbian | key | zaigang | position 
--------+----------+------+----------+-----+---------+----------
 一中   | 市教育局 | 2016 |      100 | t   |      90 | 教师
 一中   | 市教育局 | 2016 |       50 | f   |      50 | 会计
 二中   | 市教育局 | 2016 |       50 | t   |      50 | 教师


select sum(dingbian),sum(case when key then dingbian else 0 end),sum(case when key then dingbian else 0 end)/(1.0*sum(dingbian)) as pct from info group by superior;

 sum | sum |          pct           
-----+-----+------------------------
 200 | 150 | 0.75000000000000000000
(1 row)

 postgres=# select superior,sum(dingbian),sum(case when key then dingbian else 0 end),sum(case when key then dingbian else 0 end)/(1.0*sum(dingbian)) as pct from info group by superior;
 superior | sum | sum |          pct           
----------+-----+-----+------------------------
 市教育局 | 200 | 150 | 0.75000000000000000000
(1 row)

建了一个相同结构的表temptest，，也不清楚最后一项"关键岗位总人数占总定编人数缺失数"是什么意思，前面的执行结果和语句如图
语句如下：SELECT storey AS 单位,SUM(dingbian) AS 总定编人数,
SUM(CASE WHEN key=1 THEN zaigang ELSE 0 END ) AS 关键岗位总人数,
SUM(CASE WHEN key=1 THEN zaigang ELSE 0 END )/(1.0*SUM(dingbian)) AS 关键岗位总人数占总定编人数百分比
FROM temptest WHERE SUPERIOR='市教育局' and year='2016' GROUP BY storey;

楼主，请至少提供下表结构呀

单位 上级机构 年份 定编人数 是否为关键岗位 在岗人数 职位
storey SUPERIOR year dingbian key zaigang position

你需要给出创建表格的sql语句，最起码可以看出每个字段的类型等信息