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关于servlet的基础问题 求大神指教

**html代码中的表单提交后显示无法找到文件 不能转到servlet中 代码十分简单 找不出问题所在 求大神指教!!
html代码:
_

 <html>
    <head>
        <title>hello</title>
        <meta charset="utf-8">
    </head>
    <body>
        <form action="hello" method="post">
            <fieldset>
                <input name="123"/><br>
                <input type="submit" value="queding">
            </fieldset>
        </form>
    </body>
</html>
**_
 <?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
  <servlet>
    <servlet-name>hello world</servlet-name>
    <servlet-class>serverletdemo.helloworld</servlet-class>
  </servlet>
  <servlet-mapping>
    <servlet-name>hello world</servlet-name>
    <url-pattern>/hello</url-pattern>
  </servlet-mapping>    
</web-app>__


****

servlet代码:

 package serverletdemo;
import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class helloworld extends HttpServlet{
    public void service(HttpServletRequest request,HttpServletResponse response)
    throws ServletException,IOException{
        response.setContentType("text/html");
        PrintWriter pw = response.getWriter();
        pw.println("<h1>Hello World</h1>");
        pw.close();
    }
}

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4条回答 默认 最新

  • niaonao Java领域优质创作者 2017-07-12 21:45
    关注

    看配置是没错的,
    public class helloworld extends HttpServlet{
    public void service(HttpServletRequest request,HttpServletResponse response)
    throws ServletException,IOException{
    response.setContentType("text/html");
    PrintWriter pw = response.getWriter();
    pw.println("

    Hello World

    ");
    pw.close();
    }
    }
    一般继承HttpServlet的servlet中不直接使用service()方法,而是使用do方法,doGet(request,response) doPost(request,response);
    你看看是不是这里的问题
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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