想用python爬取网页信息，用Ajax分析网页结构后发现Request URL和Request Method如下：

因为是post请求，所以请求URL是不会变化的，因此需要往里添加参数，如图：

在base_url基础上传递form data之后，发现新生成的链接仍然无法跳转，不知道问题何在，爬虫新手一枚，还麻烦各位大神指教！以下为代码：

base_url = 'https://www.xuannaer.com/Plugin/transactData?'

formdata = {
    'province':'3',
    'city':'73',
    'county':'',
    'planningUse':'',
    'type': 'completion_area',
    'mint': '202010',
    'maxt': '202010'
    }

data = urllib.parse.urlencode(formdata)
url = base_url + data

headers = {
    'Accept':'application/json, text/javascript, */*; q=0.01',
    'Host':'www.xuannaer.com',
    'Referer':'https://www.xuannaer.com/hebei-shijiazhuang/dijiashuju/maxt202010mint202010',
    'User-Agent':'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.198 Safari/537.36',
    'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8',
    'X-Requested-With':'XMLHttpRequest',
    }
    
try:
    Response = requests.post(url, headers = headers)
    Response.encoding = 'utf-8-sig'
    if Response.status_code == 200:
        response = Response.text.strip()
    else:
        response = None
except requests.ConnectionError as e:
    print('Error',e.args)

关于Qt自制下拉列表控件的一些问题

好学的学渣

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