Robot Navigation 罗伯特的导航

Problem Description A robot has been sent to explore a remote planet. To specify a path the robot should take, a program is sent each day. The program consists of a sequence of the following commands: FORWARD X: move forward by X units. TURN LEFT: turn left (in place) by 90 degrees. TURN RIGHT: turn right (in place) by 90 degrees. The robot also has sensor units which allow it to obtain a map of its surrounding area. The map is represented as a grid. Some grid points contain hazards (e.g. craters) and the program must avoid these points or risk losing the robot. Naturally, if the initial location of the robot, the direction it is facing, and its destination position are known, it is best to send the shortest program (one consisting of the fewest commands) to move the robot to its destination (we do not care which direction it faces at the destination). You are more interested in knowing the number of different shortest programs that can move the robot to its destination. However, the number of shortest programs can be very large, so you are satisfied to compute the number as a remainder modulo 1,000,000. Input There will be several test cases in the input. Each test case will begin with a line with two integers N M Where N is the number of rows in the grid, and M is the number of columns in the grid (2 ≤ N, M ≤ 100). The next N lines of input will have M characters each. The characters will be one of the following: ‘.’ Indicating a navigable grid point. ‘*’ Indicating a crater (i.e. a non-navigable grid point). ‘X’ Indicating the target grid point. There will be exactly one ‘X’. ‘N’, ‘E’, ‘S’, or ‘W’ Indicating the starting point and initial heading of the robot. There will be exactly one of these. Note that the directions mirror compass directions on a map: N is North (toward the top of the grid), E is East (toward the right of the grid), S is South (toward the bottom of the grid) and W is West (toward the left of the grid). There will be no spaces and no other characters in the description of the map. The input will end with a line with two 0s. Output For each test case, output two integers on a single line, with a single space between them. The first is the length of a shortest possible program to navigate the robot from its starting point to the target, and the second is the number of different programs of that length which will get the robot to the target (modulo 1,000,000). If there is no path from the robot to the target, output two zeros separated by a single space. Output no extra spaces, and do not separate answers with blank lines. Sample Input 5 6 *....X .....* .....* .....* N....* 6 5 ....X .**** .**** .**** .**** N**** 3 3 .E. *** .X. 0 0 Sample Output 6 4 3 1 0 0

Robot 罗伯特问题

Problem Description Michael has a telecontrol robot. One day he put the robot on a loop with n cells. The cells are numbered from 1 to n clockwise. At first the robot is in cell 1. Then Michael uses a remote control to send m commands to the robot. A command will make the robot walk some distance. Unfortunately the direction part on the remote control is broken, so for every command the robot will chose a direction(clockwise or anticlockwise) randomly with equal possibility, and then walk w cells forward. Michael wants to know the possibility of the robot stopping in the cell that cell number >= l and <= r after m commands. Input There are multiple test cases. Each test case contains several lines. The first line contains four integers: above mentioned n(1≤n≤200) ,m(0≤m≤1,000,000),l,r(1≤l≤r≤n). Then m lines follow, each representing a command. A command is a integer w(1≤w≤100) representing the cell length the robot will walk for this command. The input end with n=0,m=0,l=0,r=0. You should not process this test case. Output For each test case in the input, you should output a line with the expected possibility. Output should be round to 4 digits after decimal points. Sample Input 3 1 1 2 1 5 2 4 4 1 2 0 0 0 0 Sample Output 0.5000 0.2500

Jumping Robot 跳跃的罗伯特

Problem Description Ali invents a jumping robot. This robot is controlled by a program {Di}, which is a finite sequence of non-negative “jumping distances”. The program can’t be changed once the robot is made. There are L boxes in a line. Each time the robot is placed in one of the boxes, facing left or right, and then it is turned on. It first jumps over D1 boxes, then jumps over D2 boxes ... Ali writes a capital letter in each box. The robot prints out all the letter it touches, including the initial one. Now he wants to design a program with a length of p, so that for every kind of letters in the boxes, if you carefully choose the initial position and direction of the robot, it can print out a sequence of that letter of length p. What’s the maximum possible p for the given letters in boxes? Input The input consists several testcases. The first line contains 2 integers n (4 <= n <= 8) and L (4 <= L <= 100), represents the number of different capital letters and the number of boxes. The second line contains a string whose length is exactly L, represents the letters in each box. The string only contains the first n capital letters, and each letter appears at least once in the string. Output Print an integer, the maximum length of the jumping program. Sample Input 4 15 DABCDDCCBAACBBA Sample Output 3

robotframework 执行报错command: pybot.bat --argumentfile

各位前辈们，我根据教程安装robotframework，并根据网上教程执行命令打开ride，但是run用例就报command: pybot.bat --argumentfile c:\users\zhoudn\appdata\local\temp\RIDEfc7_t_.d\argfile.txt --listener C:\Python27\lib\site-packages\robotide\contrib\testrunner\TestRunnerAgent.py:45557:False C:\Python27\Scripts\Learn_1\测试项目 [Error 267] 执行命令pybot--version，没问题 Robot Framework 3.1.2 <python on win32

大神们，请救救我——Matlab Robotic 工具箱 Link语句执行出错

源代码如下： clear; clc; L1 = Link('d', 0, 'a', 0, 'alpha', pi/2); %Link 类函数 L2 = Link('d', 0, 'a', 0.5, 'alpha', 0,'offset',pi/2); L3 = Link('d', 0, 'a', 0, 'alpha', pi/2,'offset',pi/4); L4 = Link('d', 1, 'a', 0, 'alpha', -pi/2); L5 = Link('d', 0, 'a', 0, 'alpha', pi/2); L6 = Link('d', 1, 'a', 0, 'alpha', 0); b=isrevolute(L1); %Link 类函数 robot=SerialLink([L1,L2,L3,L4,L5,L6]); %SerialLink 类函数 robot.name='带球形腕的拟人臂'; %SerialLink 属性值 robot.manuf='飘零过客'; %SerialLink 属性值 robot.display(); %Link 类函数 theta=[0 0 0 0 0 0]; robot.plot(theta); %SerialLink 类函数  请大神帮忙看看是什么问题，谢谢各位了。

Java 中Robot类的mouseMove不能正确移动

前一天还好的，第二天发现 只运行到以一个move，打开了其他软件的界面，然后鼠标就不动了，我手动点回Eclipse界面，鼠标又开始继续执行了 ``` robot = new Robot(); //点开了另一个软件然后鼠标就一直停留在这 robot.mouseMove(513, 1060); robot.delay(500); robot.mousePress(KeyEvent.BUTTON1_DOWN_MASK); robot.mouseRelease(KeyEvent.BUTTON1_DOWN_MASK); robot.delay(500); -----到这里鼠标就不会移动了 robot.mouseMove(972, 35); robot.delay(500); robot.mousePress(KeyEvent.BUTTON1_DOWN_MASK); robot.mouseRelease(KeyEvent.BUTTON1_DOWN_MASK); robot.delay(500); ``` 然后我在第二个move下加了个输出，发现已经执行了，但鼠标位置没变 后来试了下，在MyEclipse界面能够正常移动，切换到其他界面就出现上述情况

Robot Navigation 罗伯特的导航问题

Problem Description A robot has been sent to explore a remote planet. To specify a path the robot should take, a program is sent each day. The program consists of a sequence of the following commands: FORWARD X: move forward by X units. TURN LEFT: turn left (in place) by 90 degrees. TURN RIGHT: turn right (in place) by 90 degrees. The robot also has sensor units which allow it to obtain a map of its surrounding area. The map is represented as a grid. Some grid points contain hazards (e.g. craters) and the program must avoid these points or risk losing the robot. Naturally, if the initial location of the robot, the direction it is facing, and its destination position are known, it is best to send the shortest program (one consisting of the fewest commands) to move the robot to its destination (we do not care which direction it faces at the destination). You are more interested in knowing the number of different shortest programs that can move the robot to its destination. However, the number of shortest programs can be very large, so you are satisfied to compute the number as a remainder modulo 1,000,000. Input There will be several test cases in the input. Each test case will begin with a line with two integers N M Where N is the number of rows in the grid, and M is the number of columns in the grid (2 ≤ N, M ≤ 100). The next N lines of input will have M characters each. The characters will be one of the following: ‘.’ Indicating a navigable grid point. ‘*’ Indicating a crater (i.e. a non-navigable grid point). ‘X’ Indicating the target grid point. There will be exactly one ‘X’. ‘N’, ‘E’, ‘S’, or ‘W’ Indicating the starting point and initial heading of the robot. There will be exactly one of these. Note that the directions mirror compass directions on a map: N is North (toward the top of the grid), E is East (toward the right of the grid), S is South (toward the bottom of the grid) and W is West (toward the left of the grid). There will be no spaces and no other characters in the description of the map. The input will end with a line with two 0s. Output For each test case, output two integers on a single line, with a single space between them. The first is the length of a shortest possible program to navigate the robot from its starting point to the target, and the second is the number of different programs of that length which will get the robot to the target (modulo 1,000,000). If there is no path from the robot to the target, output two zeros separated by a single space. Output no extra spaces, and do not separate answers with blank lines. Sample Input 5 6 *....X .....* .....* .....* N....* 6 5 ....X .**** .**** .**** .**** N**** 3 3 .E. *** .X. 0 0 Sample Output 6 4 3 1 0 0

Eloh 用什么办法编写

Problem Description In 3201, The humans have conquered the whole universe. During the conquest ,we found lots of magical phenomena overthrown our previous cognition. For example, the Eloh is a hole like the black hole but has its own property. And if something is around the Eloh, there is a force between them, named “EF”(Eloh Force). Every Eloh has a circle area around it, and the Eloh is the center of the circle area. The circle is called “EFL” (Eloh Force Line). If there is a thing that has the mass(m) and the volume(v), the EF will satisfy the following properties: 　　1. In the EFL, EF = v / m and the force performs as the gravitational force. 　　2. Out the EFL, EF = m / v and the force performs as the repulsion force 　　 One day, Farmer John was grazing his robot cows in the universe. The number of cows is N and every cow has its own mass(mi) and volume(vi). Suddenly, he encountered such an Eloh. At first he and his cows are in the EFL. Sadly, the Eloh is swept away some of his cows that stressed the most powerful EF from the Eloh. In other words, sort all the cows’EF from large to small and choose some cows from the front to the back. Luckily, he and the rest of cows escaped to the external of the EFL. To leave the Eloh quickly, he put the reminding cows packaged as a connecting body, i.e, the overall performance of the mass M = sum(mi) (the cow[i] is not swept by the Eloh) and the volume V = sum(vi) (like the previous). Because of the panic, he don’t know exactly how many cows were swept away, just know that not all been swept away, nor is the zero. As a magical uncle grazing in the universe, Farmer John can create a wormhole through the Eloh center and the outside world. Farmer John can exchange some pair of the cows(pick some cows in the Eloh and choose the same number of cows outside the cave). The connecting body’s M and V will calculator again after exchanging. Now, Farmer John would like to know when how many cows were swept away in the beginning, there is an exchange scheme can make his EF bigger. To ensure that no two cows have the same density(m/v). Input There are multiple test cases. The first line of the case contains a number N(0 < N <= 200000) The following N lines, each of two number mi and vi.(0 < mi,vi <= 100000), the sequence will be in density ascending order. The input is terminated by a line containing 0. Output For each case of input, the output should consist of one line giving the number Q of the exchange schemes, following Q lines that contain a number K meaning if in the beginning, there are K cows swept away, Farmer John can find an exchange program to help him. Of course, you should output them from small to big. Sample Input 5 1 3 3 8 4 10 1 2 5 9 0 Sample Output 2 1 2

求助，robot framework 使用关键字openBrowser打开IE浏览器报错

报错信息:  IE的驱动和chrome和firefox一起放在python安装目录下，chrome和firefox可以正常打开，唯独IE不行。 直接在pycharm中调用selenium可以正常打开IE浏览器:  网上添加注册表的方法试过了也不行，估计不是驱动的问题，还希望大哥们帮帮忙解决一下，必须要IE浏览器。非常感谢

Robot Encryption 加密的问题

Problem Description Due to suspicion of cheaters, one of the more paranoid problem setters has started encrypting all messages to the rest of the jury before sending them. He didn't use any standard encryption, however, as he believes those are all part of a giant conspiracy network trying to crush IDI Open from the inside. Instead, he based it on the fact that the cheaters are likely to be the worst programmers. The decryption requires some programming skill, and should therefore be safe. Along with the encrypted message, he sent explanation of how to decrypt it. The only problem now is that not all jury members are able to implement the decryption. This is where we need your help. You need to help us decrypt these messages by writing a program that does the task. Decryption is performed by simulating a robots movement on a grid. The robot is initially placed in the north-west corner of the grid, facing south. The robot is a simple one, and only accepts three dierent commands: L turns the robot 90 angle to the left. R turns the robot 90 angle to the right. F moves the robot one square forward. If moving forward would cause the robot to fall of the grid, the robot instead makes a 180 angle turn without moving. Instructions to the robot is given in a series of commandsets. A commandset is a string of commands, with the possible addition of loops. A loop is given on the form "(commandset)number" where number is the number of times the commandset inside the parentheses should be run. Longer sequences of commands can be built up recursively in this fashion. More formally: commandset ::= instruction+ instruction ::= command | loop loop ::= "(" commandset ")" number command ::= R | L | F number ::= 1 |2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 The decrypted text is the text string obtained by concatenating the characters on the grid positions the robot stands on after executing each commandline. Input The first line of input gives T, the number of test scenarios. Each scenario starts with a line containing W and H, separated by a single space, describing the dimensions of the grid. Then follows H lines, each consisting of W characters, making up the grid. After this comes a line containing N, the number of commandlines, followed by the N lines the robot will be executing. Output One line per test scenario, containing the decrypted text. Notes and Constraints 0 < T <= 100 0 < W <= 50 0 < H <= 50 0 < N <= 20 Commandlines will be no longer than 50 characters, and will follow the syntax given in the problem text. No character with ASCII value lower than 32 or higher than 126 will appear on the robots grid. Sample Input 1 6 7 012345 6789AB CDEFGH IJKLMN OPQRST UVWXYZ _! .,& 12 FFL(F)5 (F)4 (LF)2 (L(R)6L)9 RFRFFF (L(F)2)2 LF FLFF FFFF LF FLFF L(F)4 Sample Output HELLO WORLD!

Robot Navigation 编写思路

Problem Description A robot has been sent to explore a remote planet. To specify a path the robot should take, a program is sent each day. The program consists of a sequence of the following commands: FORWARD X: move forward by X units. TURN LEFT: turn left (in place) by 90 degrees. TURN RIGHT: turn right (in place) by 90 degrees. The robot also has sensor units which allow it to obtain a map of its surrounding area. The map is represented as a grid. Some grid points contain hazards (e.g. craters) and the program must avoid these points or risk losing the robot. Naturally, if the initial location of the robot, the direction it is facing, and its destination position are known, it is best to send the shortest program (one consisting of the fewest commands) to move the robot to its destination (we do not care which direction it faces at the destination). You are more interested in knowing the number of different shortest programs that can move the robot to its destination. However, the number of shortest programs can be very large, so you are satisfied to compute the number as a remainder modulo 1,000,000. Input There will be several test cases in the input. Each test case will begin with a line with two integers N M Where N is the number of rows in the grid, and M is the number of columns in the grid (2 ≤ N, M ≤ 100). The next N lines of input will have M characters each. The characters will be one of the following: ‘.’ Indicating a navigable grid point. ‘*’ Indicating a crater (i.e. a non-navigable grid point). ‘X’ Indicating the target grid point. There will be exactly one ‘X’. ‘N’, ‘E’, ‘S’, or ‘W’ Indicating the starting point and initial heading of the robot. There will be exactly one of these. Note that the directions mirror compass directions on a map: N is North (toward the top of the grid), E is East (toward the right of the grid), S is South (toward the bottom of the grid) and W is West (toward the left of the grid). There will be no spaces and no other characters in the description of the map. The input will end with a line with two 0s. Output For each test case, output two integers on a single line, with a single space between them. The first is the length of a shortest possible program to navigate the robot from its starting point to the target, and the second is the number of different programs of that length which will get the robot to the target (modulo 1,000,000). If there is no path from the robot to the target, output two zeros separated by a single space. Output no extra spaces, and do not separate answers with blank lines. Sample Input 5 6 *....X .....* .....* .....* N....* 6 5 ....X .**** .**** .**** .**** N**** 3 3 .E. *** .X. 0 0 Sample Output 6 4 3 1 0 0

egret导入龙骨动画但是在浏览器上无法显示

在用egret调用龙骨动画的时候，在浏览器页面总是显示不成功 代码： ``` class Drangontest extends egret.DisplayObjectContainer{ constructor() { super(); this.addEventListener(egret.Event.ADDED_TO_STAGE,this.onAddToStage,this); } private onAddToStage(event:egret.Event): void { RES.addEventListener(RES.ResourceEvent.CONFIG_COMPLETE,this.drangon,this); RES.loadConfig("resource/resource.json","resource/"); RES.loadGroup("se"); RES.loadGroup("te"); RES.loadGroup("tepg"); } private drangon():void{ var dragonbonesData = RES.getRes( "ske" ); var textureData = RES.getRes( "tex" ); var texture = RES.getRes( "texpng" ); var dragonbonesFactory:dragonBones.EgretFactory = new dragonBones.EgretFactory(); dragonbonesFactory.addDragonBonesData(dragonBones.DataParser.parseDragonBonesData(dragonbonesData)); dragonbonesFactory.addTextureAtlas(new dragonBones.EgretTextureAtlas(texture,textureData)); var armature: dragonBones.Armature = dragonbonesFactory.buildArmature("robot"); this.addChild(armature.display); armature.display.x = 200; armature.display.y = 300; armature.display.scaleX = 0.5; armature.display.scaleY = 0.5; dragonBones.WorldClock.clock.add( armature ); armature.animation.gotoAndPlay("Run"); egret.Ticker.getInstance().register( function(frameTime:number){dragonBones.WorldClock.clock.advanceTime(0.01)}, this ); } } ``` 资源导入 ``` { "resources": [ {"name":"bgImage","type":"image","url":"assets/bg.jpg"}, {"name":"egretIcon","type":"image","url":"assets/egret_icon.png"}, {"name":"description","type":"json","url":"config/description.json"}, {"name":"ske","type":"json","url":"assets/NewProject_ske.json"}, {"name":"tex","type":"json","url":"assets/NewProject_tex.json"}, {"name":"texpng","type":"image","url":"assets/NewProject_tex.png"} ], "groups": [ {"name":"preload","keys":"bgImage,egretIcon"}, {"name":"se","keys":"ske"}, {"name":"te","keys":"tex"}, {"name":"tepg","keys":"texpng"} ] } ``` 然后再服务器端的错误提示是这样的  因为没有C币了没法悬赏了呜呜呜 先谢谢ge'we大佬

求大神解答，自定义baseAdapter报错

这是我的源码 package com.example.administrator.robot; import android.app.Activity; import android.content.Context; import android.support.v7.app.ActionBarActivity; import android.os.Bundle; import android.util.Log; import android.view.LayoutInflater; import android.view.Menu; import android.view.MenuItem; import android.view.View; import android.view.ViewGroup; import android.widget.BaseAdapter; import android.widget.ListView; import android.widget.TextView; public class MainActivity extends Activity { //String[] msgStr=new String[20]; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.test); /* for(int i=0;i<=19;i++) msgStr[i]=i+" ";*/ ListView listView=(ListView)findViewById(R.id.list); BaseAdapter baseAdapter; baseAdapter = new MyAdapter(this); listView.setAdapter(baseAdapter); } public class ViewHolder{ TextView textView; } private class MyAdapter extends BaseAdapter{ private LayoutInflater layoutInflater; private ViewHolder viewHolder; public MyAdapter(Context context){ layoutInflater=LayoutInflater.from(context); viewHolder=new ViewHolder(); } @Override public int getCount() { return 4; } @Override public Object getItem(int position) { return null; } @Override public long getItemId(int position) { return position; } @Override public View getView(int position, View convertView, ViewGroup parent) { Log.e("Tag","1"); if(convertView==null){ Log.e("Tag","1"); convertView=layoutInflater.inflate(R.layout.item_test,null); viewHolder.textView=(TextView)findViewById(R.id.test_text); convertView.setTag(viewHolder); Log.e("Tag","1"); } else{ Log.e("Tag","1"); viewHolder=(ViewHolder)convertView.getTag(); } Log.e("Tag","1"); viewHolder.textView.setText(position+""); Log.e("Tag","1"); return convertView; } } } ``` ``` 点击运行后，没有出现界面就闪退了，报错。 04-02 12:24:47.305 20818-20818/com.example.administrator.robot E/AndroidRuntime﹕ FATAL EXCEPTION: main java.lang.NullPointerException at com.example.administrator.robot.MainActivity$MyAdapter.getView(MainActivity.java:75) at android.widget.AbsListView.obtainView(AbsListView.java:2367) at android.widget.ListView.measureHeightOfChildren(ListView.java:1250) at android.widget.ListView.onMeasure(ListView.java:1162) at android.view.View.measure(View.java:15733) at android.view.ViewGroup.measureChildWithMargins(ViewGroup.java:5052) at android.widget.LinearLayout.measureChildBeforeLayout(LinearLayout.java:1411) at android.widget.LinearLayout.measureVertical(LinearLayout.java:698) at android.widget.LinearLayout.onMeasure(LinearLayout.java:588) at android.view.View.measure(View.java:15733) at android.view.ViewGroup.measureChildWithMargins(ViewGroup.java:5052) at android.widget.FrameLayout.onMeasure(FrameLayout.java:310) at android.view.View.measure(View.java:15733) at android.view.ViewGroup.measureChildWithMargins(ViewGroup.java:5052) at android.widget.LinearLayout.measureChildBeforeLayout(LinearLayout.java:1411) at android.widget.LinearLayout.measureVertical(LinearLayout.java:698) at android.widget.LinearLayout.onMeasure(LinearLayout.java:588) at android.view.View.measure(View.java:15733) at android.view.ViewGroup.measureChildWithMargins(ViewGroup.java:5052) at android.widget.FrameLayout.onMeasure(FrameLayout.java:310) at com.android.internal.policy.impl.PhoneWindow$DecorView.onMeasure(PhoneWindow.java:2298) at android.view.View.measure(View.java:15733) at android.view.ViewRootImpl.performMeasure(ViewRootImpl.java:2230) at android.view.ViewRootImpl.measureHierarchy(ViewRootImpl.java:1314) at android.view.ViewRootImpl.performTraversals(ViewRootImpl.java:1508) at android.view.ViewRootImpl.doTraversal(ViewRootImpl.java:1204) at android.view.ViewRootImpl$TraversalRunnable.run(ViewRootImpl.java:4951) at android.view.Choreographer$CallbackRecord.run(Choreographer.java:776) at android.view.Choreographer.doCallbacks(Choreographer.java:579) at android.view.Choreographer.doFrame(Choreographer.java:548) at android.view.Choreographer$FrameDisplayEventReceiver.run(Choreographer.java:762) at android.os.Handler.handleCallback(Handler.java:725) at android.os.Handler.dispatchMessage(Handler.java:92) at android.os.Looper.loop(Looper.java:153) at android.app.ActivityThread.main(ActivityThread.java:5383) at java.lang.reflect.Method.invokeNative(Native Method) at java.lang.reflect.Method.invoke(Method.java:511) at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:853) at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:620) at dalvik.system.NativeStart.main(Native Method)

Robot Motion 编程的技术

Problem Description A robot has been programmed to follow the instructions in its path. Instructions for the next direction the robot is to move are laid down in a grid. The possible instructions are N north (up the page) S south (down the page) E east (to the right on the page) W west (to the left on the page) For example, suppose the robot starts on the north (top) side of Grid 1 and starts south (down). The path the robot follows is shown. The robot goes through 10 instructions in the grid before leaving the grid. Compare what happens in Grid 2: the robot goes through 3 instructions only once, and then starts a loop through 8 instructions, and never exits. You are to write a program that determines how long it takes a robot to get out of the grid or how the robot loops around. Input There will be one or more grids for robots to navigate. The data for each is in the following form. On the first line are three integers separated by blanks: the number of rows in the grid, the number of columns in the grid, and the number of the column in which the robot enters from the north. The possible entry columns are numbered starting with one at the left. Then come the rows of the direction instructions. Each grid will have at least one and at most 10 rows and columns of instructions. The lines of instructions contain only the characters N, S, E, or W with no blanks. The end of input is indicated by a row containing 0 0 0. Output For each grid in the input there is one line of output. Either the robot follows a certain number of instructions and exits the grid on any one the four sides or else the robot follows the instructions on a certain number of locations once, and then the instructions on some number of locations repeatedly. The sample input below corresponds to the two grids above and illustrates the two forms of output. The word "step" is always immediately followed by "(s)" whether or not the number before it is 1. Sample Input 3 6 5 NEESWE WWWESS SNWWWW 4 5 1 SESWE EESNW NWEEN EWSEN 0 0 Sample Output 10 step(s) to exit 3 step(s) before a loop of 8 step(s)

Robot Motion 编写和解决

Problem Description A robot has been programmed to follow the instructions in its path. Instructions for the next direction the robot is to move are laid down in a grid. The possible instructions are N north (up the page) S south (down the page) E east (to the right on the page) W west (to the left on the page) For example, suppose the robot starts on the north (top) side of Grid 1 and starts south (down). The path the robot follows is shown. The robot goes through 10 instructions in the grid before leaving the grid. Compare what happens in Grid 2: the robot goes through 3 instructions only once, and then starts a loop through 8 instructions, and never exits. You are to write a program that determines how long it takes a robot to get out of the grid or how the robot loops around. Input There will be one or more grids for robots to navigate. The data for each is in the following form. On the first line are three integers separated by blanks: the number of rows in the grid, the number of columns in the grid, and the number of the column in which the robot enters from the north. The possible entry columns are numbered starting with one at the left. Then come the rows of the direction instructions. Each grid will have at least one and at most 10 rows and columns of instructions. The lines of instructions contain only the characters N, S, E, or W with no blanks. The end of input is indicated by a row containing 0 0 0. Output For each grid in the input there is one line of output. Either the robot follows a certain number of instructions and exits the grid on any one the four sides or else the robot follows the instructions on a certain number of locations once, and then the instructions on some number of locations repeatedly. The sample input below corresponds to the two grids above and illustrates the two forms of output. The word "step" is always immediately followed by "(s)" whether or not the number before it is 1. Sample Input 3 6 5 NEESWE WWWESS SNWWWW 4 5 1 SESWE EESNW NWEEN EWSEN 0 0 Sample Output 10 step(s) to exit 3 step(s) before a loop of 8 step(s)

运行此代码一直报错OSError: [WinError -2147221003] 找不到应用程序: 'QR.png' 求大佬帮忙看下

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