C++中while(n––)是什么意思?

C++中while(n––)是什么意思?

c++

6个回答

 while (变量)
如果变量为0,不循环,否则循环。
n-- 是n = n -1,同时表达式的值是原来的n

while (n--)
其实是
while (n != 0)
{
n = n - 1;
...
}

n每次减一,减到零为止

首先判断n的值,当大于零时进入循环,并且n自减一

当n不等于0时执行while循环中的内容,并且n自减1,一直到n等于0时跳出while循环(n还是会自减1)

n=0时候n--表示n没有减一之前的值,跳出循环后n=-1;

题目说有n个测试用例,用这个循环体就能达到题目要求

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path的寻找的计算,用的C语言的实现

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寻找两条最接近的路径的算法问题,采用C语言程序设计的办法如何解决的呢?

Problem Description JFantasy has fallen in love with a beautiful girl (An ICPC volunteer?). Every afternoon, when the sun set, the girl comes out from her dorm, walks around the campus, and returns to her dorm. The girl’s walking path can be considered as a closed polyline. A closed polyline is a curve specified by a sequence of points (P1, P2, …, Pn) so that the curve consists of the line segments P1P2, P2P3, …, Pn-1Pn, PnP1. Note that two line segments may intersect, coincide or partially coincide with each other. The points P1, P2, …, Pn are also called vertices of the polyline. While the girl is walking along the path, JFantasy is standing at some point which is not lying on the path. During the girl’s walking, the spoony boy rotates himself such that he can always see the girl directly in front of him. The boy may sometimes rotate counter-clockwise, and sometimes rotate clockwise. If the boy stands at point P, let AP denote the total degrees the boy rotate counter-clockwise, and BP denote the total degrees the boy rotate clockwise. It is not difficult to see that AP – BP is a multiple of 360, because when the girl finishes walking, the boy faces in the same direction as when the girl starts walking. We define the rotation number of P to be (AP – BP) / 360. LCQ is one of JFantasy’s G (G for good) friends. He has found JFantasy’s secret, and got an idea of making fun of him. He wants to put JFantasy at some point of which the rotation number is maximum given the walking path of the girl. To simplify the problem, we assume that the point where JFantasy can be put must be on a straight line. Formally, the problem can be stated as follows: Given the coordinates of (P1, P2, …, Pn), which specifies the girl’s walking path, you are asked to find the largest possible rotation number among all the points that are on the X axis, but not on the girl’s walking path. Input The input begins with a line containing an integer T (T<=100), which indicates the number of test cases. Each case begins with a line containing an integer N (2<=N<=1000), indicating the number of vertices of the girl’s walking path. The following N lines each contain two integers xi and yi (-1000<= xi, yi <=1000), indicating the coordinates of the ith vertex Pi. Output For each case, output the largest possible rotation number in a line. Sample Input 3 2 1 2 2 1 6 1 -1 2 -1 2 1 3 1 3 0 1 0 5 1 1 -1 0 1 -1 0 1 0 -1 Sample Output 0 0 2

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Problem Description Bill has found the perfect way to make money playing the slot machines. After months of careful research, he has finally figured out the mechanics behind how the machines operate. Now he is ready to make profit of his findings. But first an introduction to the game. A slot machine consists of a number of wheels, usually three or four, each with a number of symbols printed on it – cherries, oranges, bells, etc. – and will show one of its symbols at a given time. To play, you insert a coin, push a button and the wheels start spinning. After spinning for a while, each wheel stops – at random it seems – at one of its symbols. If all wheels stop at the same symbol, or some nice combination of symbols, the player wins. One combination that is especially desirable is having the jackpot symbol on all wheels. This combination is simply called ’jackpot’ and will make you rich for life. What Bill has discovered is that each wheel will stop at the jackpot symbol with a certain periodicity, which differs a lot between wheels. He has also figured out (after some sneeking around at the slot-machine factory) that all newly manufactured slot-machines are delivered showing the jackpot combination, and that they all have a counter at the back, telling how many times the machine has been played. This counter is always set to zero at delivery. Now, all Bill needs to do is to calculate the number of times a machine has to be played between two occurrences of the jackpot combination. We will call this number the jackpot periodicity. This is of course the same as the number of times the machine has to be played after leaving the factory, before it gives its first jackpot. Thus, with a glance at the counter on the back of a machine, Bill can figure out if it is about to give a jackpot. As Bill knows that you are a skillful computer programmer, he turns to you with the problem of calculating the jackpot periodicity. For each machine, he will give you the number of wheels, and the periodicity with which the jackpot symbol shows up on each wheel. Input One line with the number of machines n <= 20. For each machine, one line with the number of wheels w <= 5, and one line with w numbers, p1,p2,....pw,the periodicity of each wheel pk<=1000. Output One line per machine: The jackpot periodicity of the machine, if it is less than or equal to a billion (10^9), otherwise output the text ’More than a billion.’. Sample Input 1 3 10 6 15 Sample Output 30

计算海豚出水的时间,怎么采用C语言的代码的设计的方式加以有效正确实现的

Problem Description Dolphins are marine mammals that are closely related to whales and porpoises. They might have some kind of the biggest brains in the water, but are dolphins really smart? Some scientists say that they use their big brains to stay warm in the sea, rather than for lots of thinking. Obviously those scientists don’t think dolphins are smart. We know that the brain is made up of two types of cells – neurons and glia. Neurons do the thinking, while glia do things like keeping the brain warm to help the neurons. After looking at how dolphins’ brains are put together, they claim that dolphins have lots of glia and not many neurons. In order to find out how smart the dolphins are, we throw one of them into a maze we've just created, to see how long it'll take the dolphin to get out. The maze consists of nodes and bidirectional edges connecting them. The dolphin needs power to swim, so we place exactly one fish at each node for him to enjoy. The dolphin is not interested in eating the same kind of fish more than once, but he can't resist any food if it's just in front to him! As a result, the dolphin decided to PLAN a route before going, so that it will not REACH any kind of fish more than once. Given the information above, can you tell me the minimum time that the dolphin needs to get out? Input The first line consists of an integer T, indicating the number of test cases. The first line of each case consists of four integers N, M, S and E, indicating the number of nodes, the number of edges, the starting node and destination. Each of the next M lines consists of three integers U, V, C, indicating that there is an edge with length C between node U and V. It will take a dolphin C time to pass this edge. The next line consists of N integers. Ki indicates the label of which kind fishes i-th node has. Output Output the minimum time that a dolphin needs to get to the destination on a single line. If a dolphin can never get to the destination, please output -1. Constraints 0 < T <= 20 2 <= N <= 100; 0 <= M <= 10000; 0 <= S, E < N 0 <= U, V < N; 0 < C <= 1000 0 <= Ki < 1000 There may be more than one edge between two nodes, and may be loop, an edge that begins and ends both on the same vertex. All edges are bidirectional. Sample Input 2 2 1 0 1 0 1 1 0 0 4 4 0 3 0 1 1 1 3 1 0 2 2 2 3 2 0 0 1 2 Sample Output -1 4

这道题目如何解决,请帮我解答一下,谢谢

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齿轮的周期性运动的计算的问题,怎么使用C语言的程序编写的代码的技术的方式有效地很好地实现的

Problem Description Bill has found the perfect way to make money playing the slot machines. After months of careful research, he has finally figured out the mechanics behind how the machines operate. Now he is ready to make profit of his findings. But first an introduction to the game. A slot machine consists of a number of wheels, usually three or four, each with a number of symbols printed on it – cherries, oranges, bells, etc. – and will show one of its symbols at a given time. To play, you insert a coin, push a button and the wheels start spinning. After spinning for a while, each wheel stops – at random it seems – at one of its symbols. If all wheels stop at the same symbol, or some nice combination of symbols, the player wins. One combination that is especially desirable is having the jackpot symbol on all wheels. This combination is simply called ’jackpot’ and will make you rich for life. What Bill has discovered is that each wheel will stop at the jackpot symbol with a certain periodicity, which differs a lot between wheels. He has also figured out (after some sneeking around at the slot-machine factory) that all newly manufactured slot-machines are delivered showing the jackpot combination, and that they all have a counter at the back, telling how many times the machine has been played. This counter is always set to zero at delivery. Now, all Bill needs to do is to calculate the number of times a machine has to be played between two occurrences of the jackpot combination. We will call this number the jackpot periodicity. This is of course the same as the number of times the machine has to be played after leaving the factory, before it gives its first jackpot. Thus, with a glance at the counter on the back of a machine, Bill can figure out if it is about to give a jackpot. As Bill knows that you are a skillful computer programmer, he turns to you with the problem of calculating the jackpot periodicity. For each machine, he will give you the number of wheels, and the periodicity with which the jackpot symbol shows up on each wheel. Input One line with the number of machines n <= 20. For each machine, one line with the number of wheels w <= 5, and one line with w numbers, p1,p2,....pw,the periodicity of each wheel pk<=1000. Output One line per machine: The jackpot periodicity of the machine, if it is less than or equal to a billion (10^9), otherwise output the text ’More than a billion.’. Sample Input 1 3 10 6 15 Sample Output 30

在ROR中出现Access denied for user 'root'@'localhost'

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