Python多线程多进程问题

Question

新手求问，刚学习python，发现在两个线程或两个进程开启后（都有一个while循环），必须要第一个执行完成，第二个才会执行，求问为什么会这样

 import threading
import time

class Test:
    def run(self):
        threading.Thread(target=self.func1()).start()
        threading.Thread(target=self.func2()).start()

    def func1(self):
        count = 0
        while count < 3:
            print("thread1")
            count += 1
            time.sleep(2)

    def func2(self):
        count = 0
        while count < 3:
            print("thread2")
            count += 1
            time.sleep(1)


if __name__ == "__main__":
    Test().run()

 import multiprocessing
import time

class Test:
    def run(self):
        multiprocessing.Process(target=self.func1()).start()
        multiprocessing.Process(target=self.func2()).start()

    def func1(self):
        count = 0
        while count < 3:
            print("thread1")
            count += 1
            time.sleep(2)

    def func2(self):
        count = 0
        while count < 3:
            print("thread2")
            count += 1
            time.sleep(1)


if __name__ == "__main__":
    Test().run()

执行结果：

 thread1
thread1
thread1
thread2
thread2
thread2

Answer 1

你在函数传参时后面加了小括号就成函数调用了不是把函数当做参数传参
正确的代码：
import threading
import time

class Test:
def run(self):
threading.Thread(target=self.func1).start()
threading.Thread(target=self.func2).start()

def func1(self):
    count = 0
    while count < 3:
        print("thread1")
        count += 1
        time.sleep(2)

def func2(self):
    count = 0
    while count < 3:
        print("thread2")
        count += 1
        time.sleep(1)

if name == "__main__":
Test().run()

import multiprocessing
import time

class Test:
def run(self):
multiprocessing.Process(target=self.func1).start()
multiprocessing.Process(target=self.func2).start()

def func1(self):
    count = 0
    while count < 3:
        print("thread1")
        count += 1
        time.sleep(2)

def func2(self):
    count = 0
    while count < 3:
        print("thread2")
        count += 1
        time.sleep(1)

if name == "__main__":
Test().run()