qq_41265012 2018-06-18 02:25 采纳率: 70%
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PHP网站,mysql查询语句,应该怎么关联这2个查询

    function get_user($start = 0, $limit = 5) {
        $sql = "SELECT u.articles as num, u.id,u.name FROM `user` as u LIMIT $start,$limit";
        $list = array ();
        $query = $this->db->query ( $sql );
        foreach ( $query->result_array () as $model ) {
            $followed = $this->followed ( $model ['id'], $this->base->user ['id'] );
            $model ['hasfollower'] = $is_followed == 0 ? "0" : "1";
            $list [] = $model;
        }
        return $list;

    }

现在需要基于上面的数组中的id作为条件,来再次查询

 select sum(views) from topic where author=$model ['id']

那么我需要在数组每个值中输出sum(views)。

应该怎么结合。

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2条回答 默认 最新

  • 斯洛文尼亚旅游 2018-06-18 02:32
    关注

    建立一个sum(views)的试图,左链接取试图中的sum(views)列值就行了,干嘛要读2次数据库

    大概如下,没测试

     create view sumviews
    as
    select sum(views) as sumviews from topic group by author
    
      $sql = "SELECT u.articles as num, u.id,u.name,sv.sumviews FROM `user` as u left join sumviews as sv on sv.author=u.id LIMIT $start,$limit";
    
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