__小羊 2018-06-25 02:01 采纳率: 50%
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已结题

PostgreSQL 按周、按15分钟 分组统计

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  • __小羊 2018-06-25 07:23
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    解决了!
    以下是查询 周的SQL:
    SELECT
    to_char ( cda.time_point, 'yyyy ' ) || EXTRACT ( WEEK FROM cda.time_point ) :: INTEGER AS d,
    sum( cda.temperature ) AS temperature,
    cda.time_point AS times
    FROM
    config_climate_detail AS cda
    LEFT JOIN config_climate cl ON cda.pid = cl.id
    WHERE
    1 = 1
    AND to_char ( cda.time_point, 'YYYY-MM-DD HH24:MI:SS' ) BETWEEN '2014-01-01 00:00:00' AND '2018-12-12 00:00:00'
    GROUP BY
    d,
    times
    ORDER BY
    d,
    times DESC

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