必承其重 | 欲带皇冠 2009-07-17 17:53 采纳率: 0%
浏览 528
已采纳

如何替换 JavaScript 中出现的所有字符串?

I have this string:

"Test abc test test abc test test test abc test test abc"

Doing

str = str.replace('abc', '');

seems to only remove the first occurrence of abc in the string above. How can I replace all occurrences of it?

转载于:https://stackoverflow.com/questions/1144783/how-to-replace-all-occurrences-of-a-string-in-javascript

  • 写回答

30条回答 默认 最新

  • 妄徒之命 2013-07-12 01:46
    关注

    For the sake of completeness, I got to thinking about which method I should use to do this. There are basically two ways to do this as suggested by the other answers on this page.

    Note: In general, extending the built-in prototypes in JavaScript is generally not recommended. I am providing as extensions on the String prototype simply for purposes of illustration, showing different implementations of a hypothetical standard method on the String built-in prototype.


    Regular Expression Based Implementation

    String.prototype.replaceAll = function(search, replacement) {
        var target = this;
        return target.replace(new RegExp(search, 'g'), replacement);
    };
    

    Split and Join (Functional) Implementation

    String.prototype.replaceAll = function(search, replacement) {
        var target = this;
        return target.split(search).join(replacement);
    };
    

    Not knowing too much about how regular expressions work behind the scenes in terms of efficiency, I tended to lean toward the split and join implementation in the past without thinking about performance. When I did wonder which was more efficient, and by what margin, I used it as an excuse to find out.

    On my Chrome Windows 8 machine, the regular expression based implementation is the fastest, with the split and join implementation being 53% slower. Meaning the regular expressions are twice as fast for the lorem ipsum input I used.

    Check out this benchmark running these two implementations against each other.


    As noted in the comment below by @ThomasLeduc and others, there could be an issue with the regular expression-based implementation if search contains certain characters which are reserved as special characters in regular expressions. The implementation assumes that the caller will escape the string beforehand or will only pass strings that are without the characters in the table in Regular Expressions (MDN).

    MDN also provides an implementation to escape our strings. It would be nice if this was also standardized as RegExp.escape(str), but alas, it does not exist:

    function escapeRegExp(str) {
      return str.replace(/[.*+?^${}()|[\]\\]/g, "\\$&"); // $& means the whole matched string
    }
    

    We could call escapeRegExp within our String.prototype.replaceAll implementation, however, I'm not sure how much this will affect the performance (potentially even for strings for which the escape is not needed, like all alphanumeric strings).

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(29条)

报告相同问题?

悬赏问题

  • ¥20 关于#anlogic#sdram#的问题,如何解决?(关键词-performance)
  • ¥15 相敏解调 matlab
  • ¥15 求lingo代码和思路
  • ¥15 公交车和无人机协同运输
  • ¥15 stm32代码移植没反应
  • ¥15 matlab基于pde算法图像修复,为什么只能对示例图像有效
  • ¥100 连续两帧图像高速减法
  • ¥15 如何绘制动力学系统的相图
  • ¥15 对接wps接口实现获取元数据
  • ¥20 给自己本科IT专业毕业的妹m找个实习工作