【萌新求助】关于根据用户的输入来使用已有的字典

Question

from random import randint
from time import sleep

import 卡池 

stone = 100
result = []
dictionary = {}

print("欢迎来到Allen抽卡模拟器！")
tip = input("请选择卡池(test/常驻/):")
try:
	dictionary = f'{tip}'
	print(dictionary)
except:
	print("Error!")

def one():
	b = randint(1,1000)
	if b>=0 and b<=10:
		a = six_stars[randint(0,int(len(six_stars))-1)]
		result.append(a)
		print(a)
	elif b>=11 and b<=100:
		a = five_stars[randint(0,int(len(five_stars))-1)]
		result.append(a)
		print(a)
	elif b>=101 and b<=400:
		a = four_stars[randint(0,int(len(four_stars))-1)]
		result.append(a)
		print(a)	
	else:
		a = three_stars[randint(0,int(len(three_stars))-1)]
		result.append(a)
		print(a)

def ten():
    for i in range(10):
        one()

while stone > 0:
	a = input(f"\n石头数：{str(stone)}\n输入1单抽，输入2十连:\n(输入'q'以退出)")
	if a == '1':
		stone -= 1
		one()
	if a == '2':
		if stone >= 10:
			stone -= 10
			ten()
		else:
			print('石头不足！')

	if a == 'q':
		break
	while stone == 0:
		tip = input('\n石头不足，是否氪金？(y/n)')
		if tip == 'y':
			stone += 100
			print('氪金成功！')
		if tip == 'n':
			break

print('\n抽卡数：' + str(len(result)))

print("六星：",end="")
for i in six_stars:
	print(f"{i}:{str(result.count(i))}",end=" ")
print(f"\n")

print("五星：",end="")
for i in five_stars:
	print(f"{i}:{str(result.count(i))}",end=" ")
print(f"\n")

print("四星：",end="")
for i in four_stars:
	print(f"{i}:{str(result.count(i))}",end=" ")
print(f"\n")

print("三星：",end="")
for i in three_stars:
	print(f"{i}:{str(result.count(i))}",end=" ")
print(f"\n")

print('\n已退出模拟器！')

如图为一个简单的模拟抽卡程序，我的目的是让用户能自主选择卡池。

已经尝试了input()，发现只能返回一个字符串。

在线等大佬帮助！wei'x

Answer 1

import 卡池 是什么？