python统计单词词频

Question

统计Hamlet文本文件中所有的的单词词频，并把词频排名前100的单词和出现频次保存到一个文本文件中，并将文件名统一格式为“姓名.txt”

Answer 1

def getText():
    txt = open("C:/Users/Lenovo/Desktop/hamlet.txt", "r").read()
    txt = txt.lower()
    for ch in '!"#$%&()*+,-./:;<=>?@[\\]^_‘{|}~':
        txt = txt.replace(ch," ")
    return txt

hamletText = getText()
words = hamletText.split()
counts = {}
for word in words:
    counts[word] = counts.get(word,0) + 1
items = list(counts.items())
items.sort(key = lambda x:x[1],reverse = True)
a=sum([len(line.split()) for line in open("C:/Users/Lenovo/Desktop/hamlet.txt", 'r')])
#print(a)
for i in range(a-1):
    word,count = items[i]
    print("{0:<10}{1:>5}".format(word,count))

有帮助的话点个采纳，谢谢