有大神帮忙看看这个咋改吗 报错问题是没有参数列表匹配的构造函数实例

Question

#include <iostream>
#include <string>
using namespace std;
class Teacher
{
public:
    Teacher(string nam, char da, string tit, string se)
    {
        name = nam;
        date = da;
        sex = se;
        title = tit;
    }
    void display();
protected:
    string name;
    char date;
    string sex;
    string title;
};
void Teacher::display()
{
    cout << "name: " << name << endl;
    cout << "date: " << date << endl;
    cout << "sex: " << sex << endl;
    cout << "title: " << title << endl;
}
class Cadre
{
public:
    Cadre(string nam, char da, string pos, string se)
    {
        name = nam;
        date = da;
        post = pos;
        sex = se;
    }
    void display1();
protected:
    string name;
    char date;
    string post;
    string sex;
};
void Cadre::display1()
{
    cout << "name: " << name << endl;
    cout << "sex: " << sex << endl;
    cout << "date: " << date << endl;
    cout << "post: " << post << endl;
}
class Teacher_Cadre : public Teacher, public Cadre
{
public:
    Teacher_Cadre(string nam, char da, string sex, string tit, string pos,float w) :Teacher(nam, da, sex, tit), Cadre(nam, da, sex, pos)
    {
        wages = w;
    }
    void show()
    {
        Teacher::display();
        cout << "post:" << Cadre::post << endl;
        cout << "wages:" << wages << endl;
    }
private:
    float wages;
};
int main()
{
    Teacher_Cadre person1("LiHua", 0630, 'm', "professor", "assitant", 9999.9);
    person1.show();
    return 0;
}

Answer 1

类型对不上呗，你传参需要对应构造函数Teacher_Cadre(string nam, char da, string sex, string tit, string pos, float w)里的参数意义对应才行。

例如你改成如下就可以了：

Teacher_Cadre person1("LiHua", 'm', "男", "professor", "assitant", 9999.9);

这里只是举个例子，具体参数自己填写哈！

点个采纳吧！