简单计数器问题，评测结果为超时，请问该怎么改，谢谢

Question

#include<stdio.h>
int main()
{
    int a,b;
    char c;
    scanf("%d %d %c",&a,&b,&c);
    if(b==0) printf("Divided by zero!");
    if(c!='+'&&c!='-'&&c!='*'&&c!='/') 
        printf("Invalid operator!");
    if(c=='+') printf("%d",a+b);
    else if(c=='-') printf("%d",a-b);
    else if(c=='*') printf("%d",a*b);
    else if(c=='/') printf("%d",a/b);
    return 0;
} 

 

Answer 1

if(c=='+') printf("%d",a+b);
    else if(c=='-') printf("%d",a-b);
    else if(c=='*') printf("%d",a*b);
    else if(c=='/') printf("%d",a/b); 如果是除法的话，要判断四次，建议用switch...case

switch(c)
{
    case '+':
        printf("%d",a+b);
        break;
    case '-':
        printf("%d",a-b);
        break;
    case '*':
        printf("%d",a*b);
        break;
    case '/':
        printf("%d",a/b);
        break;
    default:
        printf("Invalid operator!");
        break;
}