c语言链表输不出来值

Question

# include <stdio.h>
# include <stdlib.h>

struct node
{
	int val;
	struct node *next;
};

void linked_list_insert_after(struct node *head,int n);
int linked_list_traverse(struct node *head);

int main()
{
	struct node *head=(struct node *)malloc(sizeof(struct node));
	linked_list_insert_after(head,10);
	linked_list_traverse(head);
}

void linked_list_insert_after(struct node *head,int n)
{
	struct node *node , *end ;
	int i;
	printf("请输入值\n");
	for(i=0 ; i<n ; i++ )
	{
		node=(struct node *)malloc(sizeof(struct node));
		scanf("%d",&node->val);
		node->next=NULL;
		if(i==0)
		{
			head=node;
			head->next=NULL;
			end=head;
		}
		else
		{
			end->next=node;
			end=node;
		}
	}
	end->next=NULL;
}
int linked_list_traverse(struct node *head)
{
	struct node *p=head;
	if(p==NULL)
	{
		printf("此链表为空\n");
		return -1;
	}
	else
	{	
		printf("输出链表中的值\n");
		while(p!=NULL)
		{
			printf("%d\n",p->val);
			p=p->next;
		}
		return 0;
	}
}

输不出来值

Answer 1

第25行，你把n变成n-1试试