C语言程序编程设计。

Question

Answer 1

#include <stdio.h>
void fun(int *a, int n)
{
    int t;
    for (int i = 0; i < n-1; i++)
        for (int j = 0; j < n-1-i; j++)
            if (a[j]<a[j+1])
            {
                t = a[i];
                a[i] = a[j];
                a[j] = t;
            }
}
int main()
{
    int a[3];
    int n = 3;
    for (int i = 0; i < 3; i++)
        scanf("%d", &a[i]);
    fun(a, n);
    for (int i = 0; i < n; i++)
        printf("%d ", a[i]);
}

Answer 2

第一题：

double mypow(double x,int y)
{
    int i;
    double s = 1;
    if(y==0)
        return 1;
    for(i=1;i<=y;i++)
        s = s*x;
    return s;
}

第二题：

#include <stdio.h>

void fun(int *a,int *b,int *c)
{
    int max,min;
    max = *a>(*b>*c?*b:*c)?*a:(*b>*c?*b:*c);
    min = *a<(*b<*c?*b:*c)?*a:(*b<*c?*b:*c);
    *b = *a + *b + *c - max - min;
    *a = max;
    *c = min;
}

int main()
{
    int a,b,c;
    scanf("%d %d %d",&a,&b,&c);
    fun(&a,&b,&c);
    printf("从大到小：%d %d %d\n",a,b,c);
    return 0;
}

Answer 3

#include <stdio.h>

double mypow(double x, int y)
{
    double p = 1;
    while (y)
    {
        p *= x;
        y--;
    }
    return p;
}

int main()
{
    double a = 5.0;
    int n = 5;
    printf("%lf\n", mypow(a, n));
    return 0;
}

#include <stdio.h>
void fun(int *a, int n)
{
    int t;
    for (int i = 0; i < n; i++)
        for (int j = 0; j < n; j++)
            if (a[i] > a[j])
            {
                t = a[i];
                a[i] = a[j];
                a[j] = t;
            }

    for (int i = 0; i < n; i++)
        printf("%d ", a[i]);
    printf("\n");
}

int main()
{
    int a[3];
    int n = 3;
    for (int i = 0; i < 3; i++)
        scanf("%d", &a[i]);

    fun(a, n);

    return 0;
}