java后端调用Post请求在地址后面加参数 抛异常

Question

感觉是工具类哪里配置不对

/**工具类**/
public static String sendPostTwo(String url) {
        PrintWriter out = null;
        BufferedReader in = null;
        String result = "";
        try {
            URL realUrl = new URL(url);
            // 打开和URL之间的连接
            URLConnection conn = realUrl.openConnection();
            // 设置通用的请求属性
            conn.setRequestProperty("accept", "application/json");
            conn.setRequestProperty("Content-Type", "application/json");
            // 发送POST请求必须设置如下两行
            conn.setDoOutput(true);
            conn.setDoInput(true);
            // 获取URLConnection对象对应的输出流
            out = new PrintWriter(conn.getOutputStream());
            // flush输出流的缓冲
            out.flush();
            // 定义BufferedReader输入流来读取URL的响应
            in = new BufferedReader(new InputStreamReader(conn.getInputStream()));
            String line;
            while ((line = in.readLine()) != null) {
                result += line;
            }
        } catch (Exception e) {
            System.out.println("发送 POST 请求出现异常！" + e);
            e.printStackTrace();
        }
        // 使用finally块来关闭输出流、输入流
        finally {
            try {
                if (out != null) {
                    out.close();
                }
                if (in != null) {
                    in.close();
                }
            } catch (IOException ex) {
                ex.printStackTrace();
            }
        }
        return result;
    }

/**
     * 传入的第一个方法
     * 
     * @param oaCgzbTblDic
     * @return
     */
    @PostMapping("sendPostTest01")
    public JSONObject sendPostTest01(@RequestParam("jsonData") String jsonData,
            @RequestParam("userdataID") String userdataID, @RequestParam("userId") String userId) {
        JSONObject result = new JSONObject();
        try {
            StringBuffer url = new StringBuffer();
            url.append("http://localhost:8888/imart/ThreeButtJointController/sendPostTest02?");
            url.append("jsonData=").append(jsonData);
            url.append("&").append("userdataID=").append(userdataID);
            url.append("&").append("userId=").append(userId);

            String returnMessage = HttpUtils.sendPostTwo(url.toString());

            result.put(Constants.ERROR, Constants.SUCCESS);
            result.put(Constants.MSG, Constants.SAVE_MSG_SUCC);
        } catch (Exception e) {
            e.printStackTrace();
            result.put(Constants.ERROR, Constants.FAILURE);
            result.put(Constants.MSG, Constants.Error_MSG);
        }
        return result;
    }

/**
     * 要被调用的方法
     * 
     * @param oaCgzbTblDic
     * @return
     */
    @PostMapping("sendPostTest02")
    public JSONObject sendPostTest02(@RequestParam("jsonData") String jsonData,
            @RequestParam("userdataID") String userdataID, @RequestParam("userId") String userId) {
        JSONObject result = new JSONObject();

        System.out.println("进来了+++++++++++++++++++++++++++++");
        System.out.println("jsonData:" + jsonData);
        System.out.println("userdataID:" + userdataID);
        System.out.println("userId:" + userId);
        result.put(Constants.ERROR, Constants.SUCCESS);
        result.put(Constants.MSG, Constants.SAVE_MSG_SUCC);
        try {
        } catch (Exception e) {
            result.put(Constants.ERROR, Constants.FAILURE);
            result.put(Constants.MSG, Constants.Error_MSG);
        }
        return null;
    }

postman配置

异常

java.net.MalformedURLException: Illegal character in URL

Answer 1

1,把请求的URL 打印下，看一下字符
2，你的tomcat 版本是多少？tomcat高版本中URL有些特殊字符不允许，例如 { }