这段小程序continue跳过的步骤

Question

#include<stdio.h>
int main()
{
    int guess = 1;
    char response;
    printf("is your num %d?\n",guess);
    while ((response = getchar())!= 'y')
    {
        if (response == 'n')
           printf("well,is your num is %d?\n",++guess);
        else
           printf("only y or n.\n");
        while (getchar() == '\n')
           continue;
    }
    printf("I know I could do it\n");
    return 0;
}

Answer 1

你这个continue其实不用加，直接这样就好了。因为你之前在第一次输入后，第一个回车被读入，continue跳过了此次循环进入内部while的下一次循环，当前等于回车符会继续进行一次getchar读入，把你下一次的y或者n读入了，此时跳出内部while循环，然后再大的while循环回车会被作为response读入，每次都是判断是否等于‘n’,所以一直输出only y or n.\n，去掉内部的while循环或者只用一个getchar（）问题就解决了。
如果有帮助请点一下我回答右上方的采纳，谢谢！以后有什么问题可以互相交流。

#include<stdio.h>
int main()
{
    int guess = 1;
    char response;
    printf("is your num %d?\n",guess);
    while ((response = getchar())!= 'y')
    {
        if (response == 'n')
           printf("well,is your num is %d?\n",++guess);
        else
           printf("only y or n.\n");

    }
    printf("I know I could do it\n");
    return 0;
}

或者只用一次getchar（）吃回车

#include<stdio.h>
int main()
{
    int guess = 1;
    char response;

    while ((response = getchar())!= 'y')
    {
        printf("%c\n",response);
        if (response == 'n')
           printf("well,is your num is %d?\n",++guess);
        else
           printf("only y or n.\n");
        getchar();

    }
    printf("I know I could do it\n");
    return 0;
}