关于futuretask执行任务超时测试结果不正确的问题，请问如下代码为什么部分本该正常执行的结果超时了

Question

```java
@Test
    public void test() {
        Thread thread1 = new Thread(new Thread1());
        Thread thread2 = new Thread(new Thread2());
        try {
            thread1.start();
            thread2.start();
            Thread.sleep(30000);
            thread1.interrupt();
            thread2.interrupt();
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
    }



    class Thread1 implements Runnable {
        @Override
        public void run() {
            for (int i = 0; i < 1000; i++) {
                aa(22);
            }
        }
    }

    class Thread2 implements Runnable {
        @Override
        public void run() {
            for (int i = 0; i < 1000; i++) {
                aa(103);
            }
        }
    }

    public  void aa(int a) {

        Future<Integer> future = executorService.submit(new test(a));
        try {
            Integer result = future.get(5, TimeUnit.MILLISECONDS);
            System.out.println("任务正常，" + result);
        } catch (InterruptedException | ExecutionException e) {
            System.out.println("aaaa");
        }catch (TimeoutException e){
            future.cancel(true);
            if (a==22){
                System.out.println("任务超时"+a);
            }


            //future.cancel(true);
        }
    }

    class test implements Callable<Integer>{

        private int a;

        public test(int a) {
            this.a = a;
        }

        @Override
        public Integer call() {
            long time = System.currentTimeMillis();
            while (!Thread.interrupted()){
                if (a > 100) {
                    while (!Thread.currentThread().isInterrupted()){
                        for (int i=0;i<Integer.MAX_VALUE;i++){
                            new Integer(0);
                        }
                    }

                }
                if (a < 100) {
                    System.out.println("耗时2。。。。。。"+(System.currentTimeMillis()-time));
                   return a;
                }
            }
            System.out.println("耗时。。。。。。"+(System.currentTimeMillis()-time));

            throw new RuntimeException();
        }
    }

```

Answer 1

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