这个代码为何交换不了两个整数的值？

Question

#include<stdio.h>

void swap(int a,int b)
{
    int j,k,t;
    t = j;
    j = k;
    k = t;
}
int main()
{
    int a = 3;
    int b = 5;
    swap(a , b);
    printf("%d %d\n",a,b);
    
    return 0; 
}

Answer 1

有帮助望采纳

#include <stdio.h>

void swap(int *o, int *p)
{
    int temp;
    temp = *o;
    *o = *p;
    *p = temp;
}
int main()
{
    int a = 3, b = 5;
    swap(&a, &b);
    printf("%d %d\n", a, b);
    return 0;
}